* This uses an exclusive 'or' to find that bit and then inverts it to
* form a mask, with just a single 0, in the bit position where 'S' and
* 's' differ. */
- const U8 S_or_s_mask = ~ ('S' ^ 's');
+ const U8 S_or_s_mask = (U8) ~ ('S' ^ 's');
const U8 s_masked = 's' & S_or_s_mask;
/* One pass is made over the node's string looking for all the