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1=head1 NAME
2
3perlreftut - Mark's very short tutorial about references
4
5=head1 DESCRIPTION
6
7One of the most important new features in Perl 5 was the capability to
8manage complicated data structures like multidimensional arrays and
9nested hashes. To enable these, Perl 5 introduced a feature called
ccf3535a 10'references', and using references is the key to managing complicated,
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11structured data in Perl. Unfortunately, there's a lot of funny syntax
12to learn, and the main manual page can be hard to follow. The manual
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13is quite complete, and sometimes people find that a problem, because
14it can be hard to tell what is important and what isn't.
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15
16Fortunately, you only need to know 10% of what's in the main page to get
1790% of the benefit. This page will show you that 10%.
18
19=head1 Who Needs Complicated Data Structures?
20
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21One problem that comes up all the time is needing a hash whose values are
22lists. Perl has hashes, of course, but the values have to be scalars;
23they can't be lists.
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24
25Why would you want a hash of lists? Let's take a simple example: You
1da6492a 26have a file of city and country names, like this:
a1e2a320 27
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28 Chicago, USA
29 Frankfurt, Germany
30 Berlin, Germany
31 Washington, USA
32 Helsinki, Finland
33 New York, USA
a1e2a320 34
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35and you want to produce an output like this, with each country mentioned
36once, and then an alphabetical list of the cities in that country:
a1e2a320 37
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38 Finland: Helsinki.
39 Germany: Berlin, Frankfurt.
40 USA: Chicago, New York, Washington.
a1e2a320 41
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42The natural way to do this is to have a hash whose keys are country
43names. Associated with each country name key is a list of the cities in
44that country. Each time you read a line of input, split it into a country
a1e2a320 45and a city, look up the list of cities already known to be in that
1da6492a 46country, and append the new city to the list. When you're done reading
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47the input, iterate over the hash as usual, sorting each list of cities
48before you print it out.
49
67744fad 50If hash values couldn't be lists, you lose. You'd probably have to
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51combine all the cities into a single string somehow, and then when
52time came to write the output, you'd have to break the string into a
53list, sort the list, and turn it back into a string. This is messy
54and error-prone. And it's frustrating, because Perl already has
55perfectly good lists that would solve the problem if only you could
56use them.
57
58=head1 The Solution
59
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60By the time Perl 5 rolled around, we were already stuck with this
61design: Hash values must be scalars. The solution to this is
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62references.
63
64A reference is a scalar value that I<refers to> an entire array or an
1da6492a 65entire hash (or to just about anything else). Names are one kind of
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66reference that you're already familiar with. Think of the President
67of the United States: a messy, inconvenient bag of blood and bones.
68But to talk about him, or to represent him in a computer program, all
de9b652d 69you need is the easy, convenient scalar string "Barack Obama".
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70
71References in Perl are like names for arrays and hashes. They're
72Perl's private, internal names, so you can be sure they're
de9b652d 73unambiguous. Unlike "Barack Obama", a reference only refers to one
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74thing, and you always know what it refers to. If you have a reference
75to an array, you can recover the entire array from it. If you have a
76reference to a hash, you can recover the entire hash. But the
77reference is still an easy, compact scalar value.
78
79You can't have a hash whose values are arrays; hash values can only be
80scalars. We're stuck with that. But a single reference can refer to
81an entire array, and references are scalars, so you can have a hash of
82references to arrays, and it'll act a lot like a hash of arrays, and
83it'll be just as useful as a hash of arrays.
84
1da6492a 85We'll come back to this city-country problem later, after we've seen
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86some syntax for managing references.
87
88
89=head1 Syntax
90
91There are just two ways to make a reference, and just two ways to use
92it once you have it.
93
94=head2 Making References
95
a29d1a25 96=head3 B<Make Rule 1>
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97
98If you put a C<\> in front of a variable, you get a
99reference to that variable.
100
101 $aref = \@array; # $aref now holds a reference to @array
102 $href = \%hash; # $href now holds a reference to %hash
91ee9109 103 $sref = \$scalar; # $sref now holds a reference to $scalar
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104
105Once the reference is stored in a variable like $aref or $href, you
106can copy it or store it just the same as any other scalar value:
107
108 $xy = $aref; # $xy now holds a reference to @array
109 $p[3] = $href; # $p[3] now holds a reference to %hash
110 $z = $p[3]; # $z now holds a reference to %hash
111
112
113These examples show how to make references to variables with names.
114Sometimes you want to make an array or a hash that doesn't have a
115name. This is analogous to the way you like to be able to use the
116string C<"\n"> or the number 80 without having to store it in a named
117variable first.
118
119B<Make Rule 2>
120
121C<[ ITEMS ]> makes a new, anonymous array, and returns a reference to
0c76616b 122that array. C<{ ITEMS }> makes a new, anonymous hash, and returns a
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123reference to that hash.
124
91ee9109 125 $aref = [ 1, "foo", undef, 13 ];
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126 # $aref now holds a reference to an array
127
91ee9109 128 $href = { APR => 4, AUG => 8 };
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129 # $href now holds a reference to a hash
130
131
132The references you get from rule 2 are the same kind of
133references that you get from rule 1:
134
135 # This:
136 $aref = [ 1, 2, 3 ];
137
138 # Does the same as this:
139 @array = (1, 2, 3);
140 $aref = \@array;
141
142
143The first line is an abbreviation for the following two lines, except
144that it doesn't create the superfluous array variable C<@array>.
145
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146If you write just C<[]>, you get a new, empty anonymous array.
147If you write just C<{}>, you get a new, empty anonymous hash.
148
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149
150=head2 Using References
151
152What can you do with a reference once you have it? It's a scalar
153value, and we've seen that you can store it as a scalar and get it back
154again just like any scalar. There are just two more ways to use it:
155
a29d1a25 156=head3 B<Use Rule 1>
a1e2a320 157
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158You can always use an array reference, in curly braces, in place of
159the name of an array. For example, C<@{$aref}> instead of C<@array>.
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160
161Here are some examples of that:
162
163Arrays:
164
165
166 @a @{$aref} An array
167 reverse @a reverse @{$aref} Reverse the array
168 $a[3] ${$aref}[3] An element of the array
169 $a[3] = 17; ${$aref}[3] = 17 Assigning an element
170
171
172On each line are two expressions that do the same thing. The
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173left-hand versions operate on the array C<@a>. The right-hand
174versions operate on the array that is referred to by C<$aref>. Once
175they find the array they're operating on, both versions do the same
176things to the arrays.
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177
178Using a hash reference is I<exactly> the same:
179
180 %h %{$href} A hash
181 keys %h keys %{$href} Get the keys from the hash
182 $h{'red'} ${$href}{'red'} An element of the hash
183 $h{'red'} = 17 ${$href}{'red'} = 17 Assigning an element
184
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185Whatever you want to do with a reference, B<Use Rule 1> tells you how
186to do it. You just write the Perl code that you would have written
187for doing the same thing to a regular array or hash, and then replace
188the array or hash name with C<{$reference}>. "How do I loop over an
189array when all I have is a reference?" Well, to loop over an array, you
190would write
191
192 for my $element (@array) {
193 ...
194 }
195
196so replace the array name, C<@array>, with the reference:
197
198 for my $element (@{$aref}) {
199 ...
200 }
201
202"How do I print out the contents of a hash when all I have is a
203reference?" First write the code for printing out a hash:
204
205 for my $key (keys %hash) {
206 print "$key => $hash{$key}\n";
207 }
208
209And then replace the hash name with the reference:
210
211 for my $key (keys %{$href}) {
212 print "$key => ${$href}{$key}\n";
213 }
214
215=head3 B<Use Rule 2>
a1e2a320 216
a0981a78 217B<Use Rule 1> is all you really need, because it tells you how to do
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218absolutely everything you ever need to do with references. But the
219most common thing to do with an array or a hash is to extract a single
220element, and the B<Use Rule 1> notation is cumbersome. So there is an
221abbreviation.
a1e2a320 222
c47ff5f1 223C<${$aref}[3]> is too hard to read, so you can write C<< $aref->[3] >>
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224instead.
225
226C<${$href}{red}> is too hard to read, so you can write
c47ff5f1 227C<< $href->{red} >> instead.
a1e2a320 228
c47ff5f1 229If C<$aref> holds a reference to an array, then C<< $aref->[3] >> is
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230the fourth element of the array. Don't confuse this with C<$aref[3]>,
231which is the fourth element of a totally different array, one
232deceptively named C<@aref>. C<$aref> and C<@aref> are unrelated the
233same way that C<$item> and C<@item> are.
234
c47ff5f1 235Similarly, C<< $href->{'red'} >> is part of the hash referred to by
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236the scalar variable C<$href>, perhaps even one with no name.
237C<$href{'red'}> is part of the deceptively named C<%href> hash. It's
c47ff5f1 238easy to forget to leave out the C<< -> >>, and if you do, you'll get
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239bizarre results when your program gets array and hash elements out of
240totally unexpected hashes and arrays that weren't the ones you wanted
241to use.
242
243
a29d1a25 244=head2 An Example
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245
246Let's see a quick example of how all this is useful.
247
248First, remember that C<[1, 2, 3]> makes an anonymous array containing
249C<(1, 2, 3)>, and gives you a reference to that array.
250
251Now think about
252
253 @a = ( [1, 2, 3],
254 [4, 5, 6],
255 [7, 8, 9]
256 );
257
258@a is an array with three elements, and each one is a reference to
259another array.
260
261C<$a[1]> is one of these references. It refers to an array, the array
262containing C<(4, 5, 6)>, and because it is a reference to an array,
a29d1a25 263B<Use Rule 2> says that we can write C<< $a[1]->[2] >> to get the
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264third element from that array. C<< $a[1]->[2] >> is the 6.
265Similarly, C<< $a[0]->[1] >> is the 2. What we have here is like a
266two-dimensional array; you can write C<< $a[ROW]->[COLUMN] >> to get
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267or set the element in any row and any column of the array.
268
269The notation still looks a little cumbersome, so there's one more
91ee9109 270abbreviation:
a1e2a320 271
a29d1a25 272=head2 Arrow Rule
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273
274In between two B<subscripts>, the arrow is optional.
275
c47ff5f1 276Instead of C<< $a[1]->[2] >>, we can write C<$a[1][2]>; it means the
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277same thing. Instead of C<< $a[0]->[1] = 23 >>, we can write
278C<$a[0][1] = 23>; it means the same thing.
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279
280Now it really looks like two-dimensional arrays!
281
282You can see why the arrows are important. Without them, we would have
283had to write C<${$a[1]}[2]> instead of C<$a[1][2]>. For
284three-dimensional arrays, they let us write C<$x[2][3][5]> instead of
285the unreadable C<${${$x[2]}[3]}[5]>.
286
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287=head1 Solution
288
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289Here's the answer to the problem I posed earlier, of reformatting a
290file of city and country names.
a1e2a320 291
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292 1 my %table;
293
294 2 while (<>) {
295 3 chomp;
296 4 my ($city, $country) = split /, /;
297 5 $table{$country} = [] unless exists $table{$country};
298 6 push @{$table{$country}}, $city;
299 7 }
300
301 8 foreach $country (sort keys %table) {
302 9 print "$country: ";
303 10 my @cities = @{$table{$country}};
304 11 print join ', ', sort @cities;
305 12 print ".\n";
306 13 }
307
308
309The program has two pieces: Lines 2--7 read the input and build a data
310structure, and lines 8-13 analyze the data and print out the report.
311We're going to have a hash, C<%table>, whose keys are country names,
312and whose values are references to arrays of city names. The data
313structure will look like this:
314
315
316 %table
91ee9109 317 +-------+---+
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318 | | | +-----------+--------+
319 |Germany| *---->| Frankfurt | Berlin |
320 | | | +-----------+--------+
321 +-------+---+
322 | | | +----------+
323 |Finland| *---->| Helsinki |
324 | | | +----------+
325 +-------+---+
326 | | | +---------+------------+----------+
327 | USA | *---->| Chicago | Washington | New York |
328 | | | +---------+------------+----------+
329 +-------+---+
330
331We'll look at output first. Supposing we already have this structure,
332how do we print it out?
333
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334 8 foreach $country (sort keys %table) {
335 9 print "$country: ";
336 10 my @cities = @{$table{$country}};
337 11 print join ', ', sort @cities;
338 12 print ".\n";
339 13 }
340
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341C<%table> is an
342ordinary hash, and we get a list of keys from it, sort the keys, and
343loop over the keys as usual. The only use of references is in line 10.
344C<$table{$country}> looks up the key C<$country> in the hash
345and gets the value, which is a reference to an array of cities in that country.
346B<Use Rule 1> says that
347we can recover the array by saying
348C<@{$table{$country}}>. Line 10 is just like
a1e2a320 349
a29d1a25 350 @cities = @array;
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351
352except that the name C<array> has been replaced by the reference
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353C<{$table{$country}}>. The C<@> tells Perl to get the entire array.
354Having gotten the list of cities, we sort it, join it, and print it
355out as usual.
a1e2a320 356
a29d1a25 357Lines 2-7 are responsible for building the structure in the first
0c76616b 358place. Here they are again:
a1e2a320 359
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360 2 while (<>) {
361 3 chomp;
362 4 my ($city, $country) = split /, /;
363 5 $table{$country} = [] unless exists $table{$country};
364 6 push @{$table{$country}}, $city;
365 7 }
a1e2a320 366
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367Lines 2-4 acquire a city and country name. Line 5 looks to see if the
368country is already present as a key in the hash. If it's not, the
369program uses the C<[]> notation (B<Make Rule 2>) to manufacture a new,
370empty anonymous array of cities, and installs a reference to it into
371the hash under the appropriate key.
a1e2a320 372
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373Line 6 installs the city name into the appropriate array.
374C<$table{$country}> now holds a reference to the array of cities seen
375in that country so far. Line 6 is exactly like
a1e2a320 376
a29d1a25 377 push @array, $city;
a1e2a320 378
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379except that the name C<array> has been replaced by the reference
380C<{$table{$country}}>. The C<push> adds a city name to the end of the
381referred-to array.
a1e2a320 382
a29d1a25 383There's one fine point I skipped. Line 5 is unnecessary, and we can
91ee9109 384get rid of it.
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385
386 2 while (<>) {
387 3 chomp;
388 4 my ($city, $country) = split /, /;
389 5 #### $table{$country} = [] unless exists $table{$country};
390 6 push @{$table{$country}}, $city;
391 7 }
392
393If there's already an entry in C<%table> for the current C<$country>,
394then nothing is different. Line 6 will locate the value in
395C<$table{$country}>, which is a reference to an array, and push
396C<$city> into the array. But
397what does it do when
398C<$country> holds a key, say C<Greece>, that is not yet in C<%table>?
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399
400This is Perl, so it does the exact right thing. It sees that you want
1da6492a 401to push C<Athens> onto an array that doesn't exist, so it helpfully
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402makes a new, empty, anonymous array for you, installs it into
403C<%table>, and then pushes C<Athens> onto it. This is called
ccf3535a 404'autovivification'--bringing things to life automatically. Perl saw
cc75f154 405that the key wasn't in the hash, so it created a new hash entry
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406automatically. Perl saw that you wanted to use the hash value as an
407array, so it created a new empty array and installed a reference to it
408in the hash automatically. And as usual, Perl made the array one
409element longer to hold the new city name.
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410
411=head1 The Rest
412
413I promised to give you 90% of the benefit with 10% of the details, and
414that means I left out 90% of the details. Now that you have an
415overview of the important parts, it should be easier to read the
416L<perlref> manual page, which discusses 100% of the details.
417
418Some of the highlights of L<perlref>:
419
420=over 4
421
422=item *
423
424You can make references to anything, including scalars, functions, and
425other references.
426
427=item *
428
0c76616b 429In B<Use Rule 1>, you can omit the curly brackets whenever the thing
1da6492a 430inside them is an atomic scalar variable like C<$aref>. For example,
a1e2a320 431C<@$aref> is the same as C<@{$aref}>, and C<$$aref[1]> is the same as
1da6492a 432C<${$aref}[1]>. If you're just starting out, you may want to adopt
d98d5fff 433the habit of always including the curly brackets.
a1e2a320 434
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435=item *
436
437This doesn't copy the underlying array:
438
91ee9109 439 $aref2 = $aref1;
a29d1a25 440
91ee9109 441You get two references to the same array. If you modify
a29d1a25 442C<< $aref1->[23] >> and then look at
91ee9109 443C<< $aref2->[23] >> you'll see the change.
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444
445To copy the array, use
446
447 $aref2 = [@{$aref1}];
448
449This uses C<[...]> notation to create a new anonymous array, and
450C<$aref2> is assigned a reference to the new array. The new array is
451initialized with the contents of the array referred to by C<$aref1>.
452
453Similarly, to copy an anonymous hash, you can use
454
0c76616b 455 $href2 = {%{$href1}};
a29d1a25 456
91ee9109 457=item *
a1e2a320 458
0c76616b 459To see if a variable contains a reference, use the C<ref> function. It
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460returns true if its argument is a reference. Actually it's a little
461better than that: It returns C<HASH> for hash references and C<ARRAY>
462for array references.
a1e2a320 463
91ee9109 464=item *
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465
466If you try to use a reference like a string, you get strings like
467
468 ARRAY(0x80f5dec) or HASH(0x826afc0)
469
470If you ever see a string that looks like this, you'll know you
471printed out a reference by mistake.
472
473A side effect of this representation is that you can use C<eq> to see
474if two references refer to the same thing. (But you should usually use
475C<==> instead because it's much faster.)
476
477=item *
478
479You can use a string as if it were a reference. If you use the string
480C<"foo"> as an array reference, it's taken to be a reference to the
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481array C<@foo>. This is called a I<soft reference> or I<symbolic
482reference>. The declaration C<use strict 'refs'> disables this
483feature, which can cause all sorts of trouble if you use it by accident.
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484
485=back
486
487You might prefer to go on to L<perllol> instead of L<perlref>; it
488discusses lists of lists and multidimensional arrays in detail. After
489that, you should move on to L<perldsc>; it's a Data Structure Cookbook
490that shows recipes for using and printing out arrays of hashes, hashes
491of arrays, and other kinds of data.
492
493=head1 Summary
494
495Everyone needs compound data structures, and in Perl the way you get
496them is with references. There are four important rules for managing
497references: Two for making references and two for using them. Once
498you know these rules you can do most of the important things you need
499to do with references.
500
501=head1 Credits
502
0c76616b 503Author: Mark Jason Dominus, Plover Systems (C<mjd-perl-ref+@plover.com>)
a1e2a320 504
1da6492a 505This article originally appeared in I<The Perl Journal>
91ee9109 506( http://www.tpj.com/ ) volume 3, #2. Reprinted with permission.
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507
508The original title was I<Understand References Today>.
509
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510=head2 Distribution Conditions
511
512Copyright 1998 The Perl Journal.
513
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514This documentation is free; you can redistribute it and/or modify it
515under the same terms as Perl itself.
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516
517Irrespective of its distribution, all code examples in these files are
518hereby placed into the public domain. You are permitted and
519encouraged to use this code in your own programs for fun or for profit
520as you see fit. A simple comment in the code giving credit would be
521courteous but is not required.
a1e2a320 522
a1e2a320 523
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524
525
526=cut