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1=head1 NAME
2
3perlreftut - Mark's very short tutorial about references
4
5=head1 DESCRIPTION
6
7One of the most important new features in Perl 5 was the capability to
8manage complicated data structures like multidimensional arrays and
9nested hashes. To enable these, Perl 5 introduced a feature called
10`references', and using references is the key to managing complicated,
11structured data in Perl. Unfortunately, there's a lot of funny syntax
12to learn, and the main manual page can be hard to follow. The manual
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13is quite complete, and sometimes people find that a problem, because
14it can be hard to tell what is important and what isn't.
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15
16Fortunately, you only need to know 10% of what's in the main page to get
1790% of the benefit. This page will show you that 10%.
18
19=head1 Who Needs Complicated Data Structures?
20
21One problem that came up all the time in Perl 4 was how to represent a
22hash whose values were lists. Perl 4 had hashes, of course, but the
91ee9109 23values had to be scalars; they couldn't be lists.
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24
25Why would you want a hash of lists? Let's take a simple example: You
1da6492a 26have a file of city and country names, like this:
a1e2a320 27
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28 Chicago, USA
29 Frankfurt, Germany
30 Berlin, Germany
31 Washington, USA
32 Helsinki, Finland
33 New York, USA
a1e2a320 34
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35and you want to produce an output like this, with each country mentioned
36once, and then an alphabetical list of the cities in that country:
a1e2a320 37
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38 Finland: Helsinki.
39 Germany: Berlin, Frankfurt.
40 USA: Chicago, New York, Washington.
a1e2a320 41
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42The natural way to do this is to have a hash whose keys are country
43names. Associated with each country name key is a list of the cities in
44that country. Each time you read a line of input, split it into a country
a1e2a320 45and a city, look up the list of cities already known to be in that
1da6492a 46country, and append the new city to the list. When you're done reading
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47the input, iterate over the hash as usual, sorting each list of cities
48before you print it out.
49
50If hash values can't be lists, you lose. In Perl 4, hash values can't
51be lists; they can only be strings. You lose. You'd probably have to
52combine all the cities into a single string somehow, and then when
53time came to write the output, you'd have to break the string into a
54list, sort the list, and turn it back into a string. This is messy
55and error-prone. And it's frustrating, because Perl already has
56perfectly good lists that would solve the problem if only you could
57use them.
58
59=head1 The Solution
60
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61By the time Perl 5 rolled around, we were already stuck with this
62design: Hash values must be scalars. The solution to this is
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63references.
64
65A reference is a scalar value that I<refers to> an entire array or an
1da6492a 66entire hash (or to just about anything else). Names are one kind of
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67reference that you're already familiar with. Think of the President
68of the United States: a messy, inconvenient bag of blood and bones.
69But to talk about him, or to represent him in a computer program, all
70you need is the easy, convenient scalar string "George Bush".
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71
72References in Perl are like names for arrays and hashes. They're
73Perl's private, internal names, so you can be sure they're
e937c8c3 74unambiguous. Unlike "George Bush", a reference only refers to one
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75thing, and you always know what it refers to. If you have a reference
76to an array, you can recover the entire array from it. If you have a
77reference to a hash, you can recover the entire hash. But the
78reference is still an easy, compact scalar value.
79
80You can't have a hash whose values are arrays; hash values can only be
81scalars. We're stuck with that. But a single reference can refer to
82an entire array, and references are scalars, so you can have a hash of
83references to arrays, and it'll act a lot like a hash of arrays, and
84it'll be just as useful as a hash of arrays.
85
1da6492a 86We'll come back to this city-country problem later, after we've seen
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87some syntax for managing references.
88
89
90=head1 Syntax
91
92There are just two ways to make a reference, and just two ways to use
93it once you have it.
94
95=head2 Making References
96
a29d1a25 97=head3 B<Make Rule 1>
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98
99If you put a C<\> in front of a variable, you get a
100reference to that variable.
101
102 $aref = \@array; # $aref now holds a reference to @array
103 $href = \%hash; # $href now holds a reference to %hash
91ee9109 104 $sref = \$scalar; # $sref now holds a reference to $scalar
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105
106Once the reference is stored in a variable like $aref or $href, you
107can copy it or store it just the same as any other scalar value:
108
109 $xy = $aref; # $xy now holds a reference to @array
110 $p[3] = $href; # $p[3] now holds a reference to %hash
111 $z = $p[3]; # $z now holds a reference to %hash
112
113
114These examples show how to make references to variables with names.
115Sometimes you want to make an array or a hash that doesn't have a
116name. This is analogous to the way you like to be able to use the
117string C<"\n"> or the number 80 without having to store it in a named
118variable first.
119
120B<Make Rule 2>
121
122C<[ ITEMS ]> makes a new, anonymous array, and returns a reference to
0c76616b 123that array. C<{ ITEMS }> makes a new, anonymous hash, and returns a
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124reference to that hash.
125
91ee9109 126 $aref = [ 1, "foo", undef, 13 ];
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127 # $aref now holds a reference to an array
128
91ee9109 129 $href = { APR => 4, AUG => 8 };
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130 # $href now holds a reference to a hash
131
132
133The references you get from rule 2 are the same kind of
134references that you get from rule 1:
135
136 # This:
137 $aref = [ 1, 2, 3 ];
138
139 # Does the same as this:
140 @array = (1, 2, 3);
141 $aref = \@array;
142
143
144The first line is an abbreviation for the following two lines, except
145that it doesn't create the superfluous array variable C<@array>.
146
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147If you write just C<[]>, you get a new, empty anonymous array.
148If you write just C<{}>, you get a new, empty anonymous hash.
149
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150
151=head2 Using References
152
153What can you do with a reference once you have it? It's a scalar
154value, and we've seen that you can store it as a scalar and get it back
155again just like any scalar. There are just two more ways to use it:
156
a29d1a25 157=head3 B<Use Rule 1>
a1e2a320 158
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159You can always use an array reference, in curly braces, in place of
160the name of an array. For example, C<@{$aref}> instead of C<@array>.
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161
162Here are some examples of that:
163
164Arrays:
165
166
167 @a @{$aref} An array
168 reverse @a reverse @{$aref} Reverse the array
169 $a[3] ${$aref}[3] An element of the array
170 $a[3] = 17; ${$aref}[3] = 17 Assigning an element
171
172
173On each line are two expressions that do the same thing. The
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174left-hand versions operate on the array C<@a>. The right-hand
175versions operate on the array that is referred to by C<$aref>. Once
176they find the array they're operating on, both versions do the same
177things to the arrays.
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178
179Using a hash reference is I<exactly> the same:
180
181 %h %{$href} A hash
182 keys %h keys %{$href} Get the keys from the hash
183 $h{'red'} ${$href}{'red'} An element of the hash
184 $h{'red'} = 17 ${$href}{'red'} = 17 Assigning an element
185
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186Whatever you want to do with a reference, B<Use Rule 1> tells you how
187to do it. You just write the Perl code that you would have written
188for doing the same thing to a regular array or hash, and then replace
189the array or hash name with C<{$reference}>. "How do I loop over an
190array when all I have is a reference?" Well, to loop over an array, you
191would write
192
193 for my $element (@array) {
194 ...
195 }
196
197so replace the array name, C<@array>, with the reference:
198
199 for my $element (@{$aref}) {
200 ...
201 }
202
203"How do I print out the contents of a hash when all I have is a
204reference?" First write the code for printing out a hash:
205
206 for my $key (keys %hash) {
207 print "$key => $hash{$key}\n";
208 }
209
210And then replace the hash name with the reference:
211
212 for my $key (keys %{$href}) {
213 print "$key => ${$href}{$key}\n";
214 }
215
216=head3 B<Use Rule 2>
a1e2a320 217
a0981a78 218B<Use Rule 1> is all you really need, because it tells you how to do
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219absolutely everything you ever need to do with references. But the
220most common thing to do with an array or a hash is to extract a single
221element, and the B<Use Rule 1> notation is cumbersome. So there is an
222abbreviation.
a1e2a320 223
c47ff5f1 224C<${$aref}[3]> is too hard to read, so you can write C<< $aref->[3] >>
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225instead.
226
227C<${$href}{red}> is too hard to read, so you can write
c47ff5f1 228C<< $href->{red} >> instead.
a1e2a320 229
c47ff5f1 230If C<$aref> holds a reference to an array, then C<< $aref->[3] >> is
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231the fourth element of the array. Don't confuse this with C<$aref[3]>,
232which is the fourth element of a totally different array, one
233deceptively named C<@aref>. C<$aref> and C<@aref> are unrelated the
234same way that C<$item> and C<@item> are.
235
c47ff5f1 236Similarly, C<< $href->{'red'} >> is part of the hash referred to by
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237the scalar variable C<$href>, perhaps even one with no name.
238C<$href{'red'}> is part of the deceptively named C<%href> hash. It's
c47ff5f1 239easy to forget to leave out the C<< -> >>, and if you do, you'll get
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240bizarre results when your program gets array and hash elements out of
241totally unexpected hashes and arrays that weren't the ones you wanted
242to use.
243
244
a29d1a25 245=head2 An Example
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246
247Let's see a quick example of how all this is useful.
248
249First, remember that C<[1, 2, 3]> makes an anonymous array containing
250C<(1, 2, 3)>, and gives you a reference to that array.
251
252Now think about
253
254 @a = ( [1, 2, 3],
255 [4, 5, 6],
256 [7, 8, 9]
257 );
258
259@a is an array with three elements, and each one is a reference to
260another array.
261
262C<$a[1]> is one of these references. It refers to an array, the array
263containing C<(4, 5, 6)>, and because it is a reference to an array,
a29d1a25 264B<Use Rule 2> says that we can write C<< $a[1]->[2] >> to get the
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265third element from that array. C<< $a[1]->[2] >> is the 6.
266Similarly, C<< $a[0]->[1] >> is the 2. What we have here is like a
267two-dimensional array; you can write C<< $a[ROW]->[COLUMN] >> to get
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268or set the element in any row and any column of the array.
269
270The notation still looks a little cumbersome, so there's one more
91ee9109 271abbreviation:
a1e2a320 272
a29d1a25 273=head2 Arrow Rule
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274
275In between two B<subscripts>, the arrow is optional.
276
c47ff5f1 277Instead of C<< $a[1]->[2] >>, we can write C<$a[1][2]>; it means the
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278same thing. Instead of C<< $a[0]->[1] = 23 >>, we can write
279C<$a[0][1] = 23>; it means the same thing.
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280
281Now it really looks like two-dimensional arrays!
282
283You can see why the arrows are important. Without them, we would have
284had to write C<${$a[1]}[2]> instead of C<$a[1][2]>. For
285three-dimensional arrays, they let us write C<$x[2][3][5]> instead of
286the unreadable C<${${$x[2]}[3]}[5]>.
287
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288=head1 Solution
289
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290Here's the answer to the problem I posed earlier, of reformatting a
291file of city and country names.
a1e2a320 292
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293 1 my %table;
294
295 2 while (<>) {
296 3 chomp;
297 4 my ($city, $country) = split /, /;
298 5 $table{$country} = [] unless exists $table{$country};
299 6 push @{$table{$country}}, $city;
300 7 }
301
302 8 foreach $country (sort keys %table) {
303 9 print "$country: ";
304 10 my @cities = @{$table{$country}};
305 11 print join ', ', sort @cities;
306 12 print ".\n";
307 13 }
308
309
310The program has two pieces: Lines 2--7 read the input and build a data
311structure, and lines 8-13 analyze the data and print out the report.
312We're going to have a hash, C<%table>, whose keys are country names,
313and whose values are references to arrays of city names. The data
314structure will look like this:
315
316
317 %table
91ee9109 318 +-------+---+
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319 | | | +-----------+--------+
320 |Germany| *---->| Frankfurt | Berlin |
321 | | | +-----------+--------+
322 +-------+---+
323 | | | +----------+
324 |Finland| *---->| Helsinki |
325 | | | +----------+
326 +-------+---+
327 | | | +---------+------------+----------+
328 | USA | *---->| Chicago | Washington | New York |
329 | | | +---------+------------+----------+
330 +-------+---+
331
332We'll look at output first. Supposing we already have this structure,
333how do we print it out?
334
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335 8 foreach $country (sort keys %table) {
336 9 print "$country: ";
337 10 my @cities = @{$table{$country}};
338 11 print join ', ', sort @cities;
339 12 print ".\n";
340 13 }
341
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342C<%table> is an
343ordinary hash, and we get a list of keys from it, sort the keys, and
344loop over the keys as usual. The only use of references is in line 10.
345C<$table{$country}> looks up the key C<$country> in the hash
346and gets the value, which is a reference to an array of cities in that country.
347B<Use Rule 1> says that
348we can recover the array by saying
349C<@{$table{$country}}>. Line 10 is just like
a1e2a320 350
a29d1a25 351 @cities = @array;
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352
353except that the name C<array> has been replaced by the reference
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354C<{$table{$country}}>. The C<@> tells Perl to get the entire array.
355Having gotten the list of cities, we sort it, join it, and print it
356out as usual.
a1e2a320 357
a29d1a25 358Lines 2-7 are responsible for building the structure in the first
0c76616b 359place. Here they are again:
a1e2a320 360
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361 2 while (<>) {
362 3 chomp;
363 4 my ($city, $country) = split /, /;
364 5 $table{$country} = [] unless exists $table{$country};
365 6 push @{$table{$country}}, $city;
366 7 }
a1e2a320 367
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368Lines 2-4 acquire a city and country name. Line 5 looks to see if the
369country is already present as a key in the hash. If it's not, the
370program uses the C<[]> notation (B<Make Rule 2>) to manufacture a new,
371empty anonymous array of cities, and installs a reference to it into
372the hash under the appropriate key.
a1e2a320 373
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374Line 6 installs the city name into the appropriate array.
375C<$table{$country}> now holds a reference to the array of cities seen
376in that country so far. Line 6 is exactly like
a1e2a320 377
a29d1a25 378 push @array, $city;
a1e2a320 379
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380except that the name C<array> has been replaced by the reference
381C<{$table{$country}}>. The C<push> adds a city name to the end of the
382referred-to array.
a1e2a320 383
a29d1a25 384There's one fine point I skipped. Line 5 is unnecessary, and we can
91ee9109 385get rid of it.
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386
387 2 while (<>) {
388 3 chomp;
389 4 my ($city, $country) = split /, /;
390 5 #### $table{$country} = [] unless exists $table{$country};
391 6 push @{$table{$country}}, $city;
392 7 }
393
394If there's already an entry in C<%table> for the current C<$country>,
395then nothing is different. Line 6 will locate the value in
396C<$table{$country}>, which is a reference to an array, and push
397C<$city> into the array. But
398what does it do when
399C<$country> holds a key, say C<Greece>, that is not yet in C<%table>?
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400
401This is Perl, so it does the exact right thing. It sees that you want
1da6492a 402to push C<Athens> onto an array that doesn't exist, so it helpfully
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403makes a new, empty, anonymous array for you, installs it into
404C<%table>, and then pushes C<Athens> onto it. This is called
405`autovivification'--bringing things to life automatically. Perl saw
406that they key wasn't in the hash, so it created a new hash entry
407automatically. Perl saw that you wanted to use the hash value as an
408array, so it created a new empty array and installed a reference to it
409in the hash automatically. And as usual, Perl made the array one
410element longer to hold the new city name.
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411
412=head1 The Rest
413
414I promised to give you 90% of the benefit with 10% of the details, and
415that means I left out 90% of the details. Now that you have an
416overview of the important parts, it should be easier to read the
417L<perlref> manual page, which discusses 100% of the details.
418
419Some of the highlights of L<perlref>:
420
421=over 4
422
423=item *
424
425You can make references to anything, including scalars, functions, and
426other references.
427
428=item *
429
0c76616b 430In B<Use Rule 1>, you can omit the curly brackets whenever the thing
1da6492a 431inside them is an atomic scalar variable like C<$aref>. For example,
a1e2a320 432C<@$aref> is the same as C<@{$aref}>, and C<$$aref[1]> is the same as
1da6492a 433C<${$aref}[1]>. If you're just starting out, you may want to adopt
d98d5fff 434the habit of always including the curly brackets.
a1e2a320 435
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436=item *
437
438This doesn't copy the underlying array:
439
91ee9109 440 $aref2 = $aref1;
a29d1a25 441
91ee9109 442You get two references to the same array. If you modify
a29d1a25 443C<< $aref1->[23] >> and then look at
91ee9109 444C<< $aref2->[23] >> you'll see the change.
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445
446To copy the array, use
447
448 $aref2 = [@{$aref1}];
449
450This uses C<[...]> notation to create a new anonymous array, and
451C<$aref2> is assigned a reference to the new array. The new array is
452initialized with the contents of the array referred to by C<$aref1>.
453
454Similarly, to copy an anonymous hash, you can use
455
0c76616b 456 $href2 = {%{$href1}};
a29d1a25 457
91ee9109 458=item *
a1e2a320 459
0c76616b 460To see if a variable contains a reference, use the C<ref> function. It
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461returns true if its argument is a reference. Actually it's a little
462better than that: It returns C<HASH> for hash references and C<ARRAY>
463for array references.
a1e2a320 464
91ee9109 465=item *
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466
467If you try to use a reference like a string, you get strings like
468
469 ARRAY(0x80f5dec) or HASH(0x826afc0)
470
471If you ever see a string that looks like this, you'll know you
472printed out a reference by mistake.
473
474A side effect of this representation is that you can use C<eq> to see
475if two references refer to the same thing. (But you should usually use
476C<==> instead because it's much faster.)
477
478=item *
479
480You can use a string as if it were a reference. If you use the string
481C<"foo"> as an array reference, it's taken to be a reference to the
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482array C<@foo>. This is called a I<soft reference> or I<symbolic
483reference>. The declaration C<use strict 'refs'> disables this
484feature, which can cause all sorts of trouble if you use it by accident.
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485
486=back
487
488You might prefer to go on to L<perllol> instead of L<perlref>; it
489discusses lists of lists and multidimensional arrays in detail. After
490that, you should move on to L<perldsc>; it's a Data Structure Cookbook
491that shows recipes for using and printing out arrays of hashes, hashes
492of arrays, and other kinds of data.
493
494=head1 Summary
495
496Everyone needs compound data structures, and in Perl the way you get
497them is with references. There are four important rules for managing
498references: Two for making references and two for using them. Once
499you know these rules you can do most of the important things you need
500to do with references.
501
502=head1 Credits
503
0c76616b 504Author: Mark Jason Dominus, Plover Systems (C<mjd-perl-ref+@plover.com>)
a1e2a320 505
1da6492a 506This article originally appeared in I<The Perl Journal>
91ee9109 507( http://www.tpj.com/ ) volume 3, #2. Reprinted with permission.
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508
509The original title was I<Understand References Today>.
510
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511=head2 Distribution Conditions
512
513Copyright 1998 The Perl Journal.
514
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515This documentation is free; you can redistribute it and/or modify it
516under the same terms as Perl itself.
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517
518Irrespective of its distribution, all code examples in these files are
519hereby placed into the public domain. You are permitted and
520encouraged to use this code in your own programs for fun or for profit
521as you see fit. A simple comment in the code giving credit would be
522courteous but is not required.
a1e2a320 523
a1e2a320 524
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525
526
527=cut