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1
2=head1 NAME
3
4perlreftut - Mark's very short tutorial about references
5
6=head1 DESCRIPTION
7
8One of the most important new features in Perl 5 was the capability to
9manage complicated data structures like multidimensional arrays and
10nested hashes. To enable these, Perl 5 introduced a feature called
11`references', and using references is the key to managing complicated,
12structured data in Perl. Unfortunately, there's a lot of funny syntax
13to learn, and the main manual page can be hard to follow. The manual
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14is quite complete, and sometimes people find that a problem, because
15it can be hard to tell what is important and what isn't.
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16
17Fortunately, you only need to know 10% of what's in the main page to get
1890% of the benefit. This page will show you that 10%.
19
20=head1 Who Needs Complicated Data Structures?
21
22One problem that came up all the time in Perl 4 was how to represent a
23hash whose values were lists. Perl 4 had hashes, of course, but the
24values had to be scalars; they couldn't be lists.
25
26Why would you want a hash of lists? Let's take a simple example: You
1da6492a 27have a file of city and country names, like this:
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29 Chicago, USA
30 Frankfurt, Germany
31 Berlin, Germany
32 Washington, USA
33 Helsinki, Finland
34 New York, USA
a1e2a320 35
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36and you want to produce an output like this, with each country mentioned
37once, and then an alphabetical list of the cities in that country:
a1e2a320 38
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39 Finland: Helsinki.
40 Germany: Berlin, Frankfurt.
41 USA: Chicago, New York, Washington.
a1e2a320 42
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43The natural way to do this is to have a hash whose keys are country
44names. Associated with each country name key is a list of the cities in
45that country. Each time you read a line of input, split it into a country
a1e2a320 46and a city, look up the list of cities already known to be in that
1da6492a 47country, and append the new city to the list. When you're done reading
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48the input, iterate over the hash as usual, sorting each list of cities
49before you print it out.
50
51If hash values can't be lists, you lose. In Perl 4, hash values can't
52be lists; they can only be strings. You lose. You'd probably have to
53combine all the cities into a single string somehow, and then when
54time came to write the output, you'd have to break the string into a
55list, sort the list, and turn it back into a string. This is messy
56and error-prone. And it's frustrating, because Perl already has
57perfectly good lists that would solve the problem if only you could
58use them.
59
60=head1 The Solution
61
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62By the time Perl 5 rolled around, we were already stuck with this
63design: Hash values must be scalars. The solution to this is
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64references.
65
66A reference is a scalar value that I<refers to> an entire array or an
1da6492a 67entire hash (or to just about anything else). Names are one kind of
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68reference that you're already familiar with. Think of the President:
69a messy, inconvenient bag of blood and bones. But to talk about him,
70or to represent him in a computer program, all you need is the easy,
71convenient scalar string "Bill Clinton".
72
73References in Perl are like names for arrays and hashes. They're
74Perl's private, internal names, so you can be sure they're
75unambiguous. Unlike "Bill Clinton", a reference only refers to one
76thing, and you always know what it refers to. If you have a reference
77to an array, you can recover the entire array from it. If you have a
78reference to a hash, you can recover the entire hash. But the
79reference is still an easy, compact scalar value.
80
81You can't have a hash whose values are arrays; hash values can only be
82scalars. We're stuck with that. But a single reference can refer to
83an entire array, and references are scalars, so you can have a hash of
84references to arrays, and it'll act a lot like a hash of arrays, and
85it'll be just as useful as a hash of arrays.
86
1da6492a 87We'll come back to this city-country problem later, after we've seen
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88some syntax for managing references.
89
90
91=head1 Syntax
92
93There are just two ways to make a reference, and just two ways to use
94it once you have it.
95
96=head2 Making References
97
98B<Make Rule 1>
99
100If you put a C<\> in front of a variable, you get a
101reference to that variable.
102
103 $aref = \@array; # $aref now holds a reference to @array
104 $href = \%hash; # $href now holds a reference to %hash
105
106Once the reference is stored in a variable like $aref or $href, you
107can copy it or store it just the same as any other scalar value:
108
109 $xy = $aref; # $xy now holds a reference to @array
110 $p[3] = $href; # $p[3] now holds a reference to %hash
111 $z = $p[3]; # $z now holds a reference to %hash
112
113
114These examples show how to make references to variables with names.
115Sometimes you want to make an array or a hash that doesn't have a
116name. This is analogous to the way you like to be able to use the
117string C<"\n"> or the number 80 without having to store it in a named
118variable first.
119
120B<Make Rule 2>
121
122C<[ ITEMS ]> makes a new, anonymous array, and returns a reference to
123that array. C<{ ITEMS }> makes a new, anonymous hash. and returns a
124reference to that hash.
125
126 $aref = [ 1, "foo", undef, 13 ];
127 # $aref now holds a reference to an array
128
129 $href = { APR => 4, AUG => 8 };
130 # $href now holds a reference to a hash
131
132
133The references you get from rule 2 are the same kind of
134references that you get from rule 1:
135
136 # This:
137 $aref = [ 1, 2, 3 ];
138
139 # Does the same as this:
140 @array = (1, 2, 3);
141 $aref = \@array;
142
143
144The first line is an abbreviation for the following two lines, except
145that it doesn't create the superfluous array variable C<@array>.
146
147
148=head2 Using References
149
150What can you do with a reference once you have it? It's a scalar
151value, and we've seen that you can store it as a scalar and get it back
152again just like any scalar. There are just two more ways to use it:
153
154B<Use Rule 1>
155
156If C<$aref> contains a reference to an array, then you
157can put C<{$aref}> anywhere you would normally put the name of an
158array. For example, C<@{$aref}> instead of C<@array>.
159
160Here are some examples of that:
161
162Arrays:
163
164
165 @a @{$aref} An array
166 reverse @a reverse @{$aref} Reverse the array
167 $a[3] ${$aref}[3] An element of the array
168 $a[3] = 17; ${$aref}[3] = 17 Assigning an element
169
170
171On each line are two expressions that do the same thing. The
172left-hand versions operate on the array C<@a>, and the right-hand
173versions operate on the array that is referred to by C<$aref>, but
174once they find the array they're operating on, they do the same things
175to the arrays.
176
177Using a hash reference is I<exactly> the same:
178
179 %h %{$href} A hash
180 keys %h keys %{$href} Get the keys from the hash
181 $h{'red'} ${$href}{'red'} An element of the hash
182 $h{'red'} = 17 ${$href}{'red'} = 17 Assigning an element
183
184
185B<Use Rule 2>
186
c47ff5f1 187C<${$aref}[3]> is too hard to read, so you can write C<< $aref->[3] >>
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188instead.
189
190C<${$href}{red}> is too hard to read, so you can write
c47ff5f1 191C<< $href->{red} >> instead.
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192
193Most often, when you have an array or a hash, you want to get or set a
194single element from it. C<${$aref}[3]> and C<${$href}{'red'}> have
195too much punctuation, and Perl lets you abbreviate.
196
c47ff5f1 197If C<$aref> holds a reference to an array, then C<< $aref->[3] >> is
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198the fourth element of the array. Don't confuse this with C<$aref[3]>,
199which is the fourth element of a totally different array, one
200deceptively named C<@aref>. C<$aref> and C<@aref> are unrelated the
201same way that C<$item> and C<@item> are.
202
c47ff5f1 203Similarly, C<< $href->{'red'} >> is part of the hash referred to by
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204the scalar variable C<$href>, perhaps even one with no name.
205C<$href{'red'}> is part of the deceptively named C<%href> hash. It's
c47ff5f1 206easy to forget to leave out the C<< -> >>, and if you do, you'll get
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207bizarre results when your program gets array and hash elements out of
208totally unexpected hashes and arrays that weren't the ones you wanted
209to use.
210
211
212=head1 An Example
213
214Let's see a quick example of how all this is useful.
215
216First, remember that C<[1, 2, 3]> makes an anonymous array containing
217C<(1, 2, 3)>, and gives you a reference to that array.
218
219Now think about
220
221 @a = ( [1, 2, 3],
222 [4, 5, 6],
223 [7, 8, 9]
224 );
225
226@a is an array with three elements, and each one is a reference to
227another array.
228
229C<$a[1]> is one of these references. It refers to an array, the array
230containing C<(4, 5, 6)>, and because it is a reference to an array,
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231B<USE RULE 2> says that we can write C<< $a[1]->[2] >> to get the
232third element from that array. C<< $a[1]->[2] >> is the 6.
233Similarly, C<< $a[0]->[1] >> is the 2. What we have here is like a
234two-dimensional array; you can write C<< $a[ROW]->[COLUMN] >> to get
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235or set the element in any row and any column of the array.
236
237The notation still looks a little cumbersome, so there's one more
238abbreviation:
239
240=head1 Arrow Rule
241
242In between two B<subscripts>, the arrow is optional.
243
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244Instead of C<< $a[1]->[2] >>, we can write C<$a[1][2]>; it means the
245same thing. Instead of C<< $a[0]->[1] >>, we can write C<$a[0][1]>;
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246it means the same thing.
247
248Now it really looks like two-dimensional arrays!
249
250You can see why the arrows are important. Without them, we would have
251had to write C<${$a[1]}[2]> instead of C<$a[1][2]>. For
252three-dimensional arrays, they let us write C<$x[2][3][5]> instead of
253the unreadable C<${${$x[2]}[3]}[5]>.
254
255
256=head1 Solution
257
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258Here's the answer to the problem I posed earlier, of reformatting a
259file of city and country names.
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260
261 1 while (<>) {
262 2 chomp;
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263 3 my ($city, $country) = split /, /;
264 4 push @{$table{$country}}, $city;
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265 5 }
266 6
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267 7 foreach $country (sort keys %table) {
268 8 print "$country: ";
269 9 my @cities = @{$table{$country}};
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270 10 print join ', ', sort @cities;
271 11 print ".\n";
272 12 }
273
274
275The program has two pieces: Lines 1--5 read the input and build a
276data structure, and lines 7--12 analyze the data and print out the
277report.
278
279In the first part, line 4 is the important one. We're going to have a
1da6492a 280hash, C<%table>, whose keys are country names, and whose values are
a1e2a320 281(references to) arrays of city names. After acquiring a city and
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282country name, the program looks up C<$table{$country}>, which holds (a
283reference to) the list of cities seen in that country so far. Line 4 is
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284totally analogous to
285
286 push @array, $city;
287
288except that the name C<array> has been replaced by the reference
1da6492a 289C<{$table{$country}}>. The C<push> adds a city name to the end of the
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290referred-to array.
291
292In the second part, line 9 is the important one. Again,
1da6492a 293C<$table{$country}> is (a reference to) the list of cities in the country, so
a1e2a320 294we can recover the original list, and copy it into the array C<@cities>,
1da6492a 295by using C<@{$table{$country}}>. Line 9 is totally analogous to
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296
297 @cities = @array;
298
299except that the name C<array> has been replaced by the reference
1da6492a 300C<{$table{$country}}>. The C<@> tells Perl to get the entire array.
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301
302The rest of the program is just familiar uses of C<chomp>, C<split>, C<sort>,
303C<print>, and doesn't involve references at all.
304
305There's one fine point I skipped. Suppose the program has just read
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306the first line in its input that happens to mention Greece.
307Control is at line 4, C<$country> is C<'Greece'>, and C<$city> is
308C<'Athens'>. Since this is the first city in Greece,
309C<$table{$country}> is undefined---in fact there isn't an C<'Greece'> key
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310in C<%table> at all. What does line 4 do here?
311
1da6492a 312 4 push @{$table{$country}}, $city;
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313
314
315This is Perl, so it does the exact right thing. It sees that you want
1da6492a 316to push C<Athens> onto an array that doesn't exist, so it helpfully
a1e2a320 317makes a new, empty, anonymous array for you, installs it in the table,
1da6492a 318and then pushes C<Athens> onto it. This is called `autovivification'.
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319
320
321=head1 The Rest
322
323I promised to give you 90% of the benefit with 10% of the details, and
324that means I left out 90% of the details. Now that you have an
325overview of the important parts, it should be easier to read the
326L<perlref> manual page, which discusses 100% of the details.
327
328Some of the highlights of L<perlref>:
329
330=over 4
331
332=item *
333
334You can make references to anything, including scalars, functions, and
335other references.
336
337=item *
338
d98d5fff 339In B<USE RULE 1>, you can omit the curly brackets whenever the thing
1da6492a 340inside them is an atomic scalar variable like C<$aref>. For example,
a1e2a320 341C<@$aref> is the same as C<@{$aref}>, and C<$$aref[1]> is the same as
1da6492a 342C<${$aref}[1]>. If you're just starting out, you may want to adopt
d98d5fff 343the habit of always including the curly brackets.
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344
345=item *
346
347To see if a variable contains a reference, use the `ref' function.
348It returns true if its argument is a reference. Actually it's a
349little better than that: It returns HASH for hash references and
1da6492a 350ARRAY for array references.
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351
352=item *
353
354If you try to use a reference like a string, you get strings like
355
356 ARRAY(0x80f5dec) or HASH(0x826afc0)
357
358If you ever see a string that looks like this, you'll know you
359printed out a reference by mistake.
360
361A side effect of this representation is that you can use C<eq> to see
362if two references refer to the same thing. (But you should usually use
363C<==> instead because it's much faster.)
364
365=item *
366
367You can use a string as if it were a reference. If you use the string
368C<"foo"> as an array reference, it's taken to be a reference to the
369array C<@foo>. This is called a I<soft reference> or I<symbolic reference>.
370
371=back
372
373You might prefer to go on to L<perllol> instead of L<perlref>; it
374discusses lists of lists and multidimensional arrays in detail. After
375that, you should move on to L<perldsc>; it's a Data Structure Cookbook
376that shows recipes for using and printing out arrays of hashes, hashes
377of arrays, and other kinds of data.
378
379=head1 Summary
380
381Everyone needs compound data structures, and in Perl the way you get
382them is with references. There are four important rules for managing
383references: Two for making references and two for using them. Once
384you know these rules you can do most of the important things you need
385to do with references.
386
387=head1 Credits
388
fd97da5a 389Author: Mark-Jason Dominus, Plover Systems (C<mjd-perl-ref+@plover.com>)
a1e2a320 390
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391This article originally appeared in I<The Perl Journal>
392(http://tpj.com) volume 3, #2. Reprinted with permission.
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393
394The original title was I<Understand References Today>.
395
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396=head2 Distribution Conditions
397
398Copyright 1998 The Perl Journal.
399
400When included as part of the Standard Version of Perl, or as part of
401its complete documentation whether printed or otherwise, this work may
402be distributed only under the terms of Perl's Artistic License. Any
403distribution of this file or derivatives thereof outside of that
404package require that special arrangements be made with copyright
405holder.
406
407Irrespective of its distribution, all code examples in these files are
408hereby placed into the public domain. You are permitted and
409encouraged to use this code in your own programs for fun or for profit
410as you see fit. A simple comment in the code giving credit would be
411courteous but is not required.
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414
415
416=cut