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1=head1 NAME
2
3perlpacktut - tutorial on C<pack> and C<unpack>
4
5=head1 DESCRIPTION
6
7C<pack> and C<unpack> are two functions for transforming data according
8to a user-defined template, between the guarded way Perl stores values
47b6252e 9and some well-defined representation as might be required in the
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10environment of a Perl program. Unfortunately, they're also two of
11the most misunderstood and most often overlooked functions that Perl
12provides. This tutorial will demystify them for you.
13
14
15=head1 The Basic Principle
16
17Most programming languages don't shelter the memory where variables are
18stored. In C, for instance, you can take the address of some variable,
19and the C<sizeof> operator tells you how many bytes are allocated to
20the variable. Using the address and the size, you may access the storage
21to your heart's content.
22
23In Perl, you just can't access memory at random, but the structural and
24representational conversion provided by C<pack> and C<unpack> is an
25excellent alternative. The C<pack> function converts values to a byte
26sequence containing representations according to a given specification,
27the so-called "template" argument. C<unpack> is the reverse process,
28deriving some values from the contents of a string of bytes. (Be cautioned,
29however, that not all that has been packed together can be neatly unpacked -
30a very common experience as seasoned travellers are likely to confirm.)
31
32Why, you may ask, would you need a chunk of memory containing some values
33in binary representation? One good reason is input and output accessing
34some file, a device, or a network connection, whereby this binary
35representation is either forced on you or will give you some benefit
36in processing. Another cause is passing data to some system call that
37is not available as a Perl function: C<syscall> requires you to provide
38parameters stored in the way it happens in a C program. Even text processing
39(as shown in the next section) may be simplified with judicious usage
40of these two functions.
41
42To see how (un)packing works, we'll start with a simple template
43code where the conversion is in low gear: between the contents of a byte
44sequence and a string of hexadecimal digits. Let's use C<unpack>, since
47b6252e 45this is likely to remind you of a dump program, or some desperate last
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46message unfortunate programs are wont to throw at you before they expire
47into the wild blue yonder. Assuming that the variable C<$mem> holds a
48sequence of bytes that we'd like to inspect without assuming anything
49about its meaning, we can write
50
51 my( $hex ) = unpack( 'H*', $mem );
52 print "$hex\n";
53
54whereupon we might see something like this, with each pair of hex digits
55corresponding to a byte:
56
57 41204d414e204120504c414e20412043414e414c2050414e414d41
58
47b6252e 59What was in this chunk of memory? Numbers, characters, or a mixture of
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60both? Assuming that we're on a computer where ASCII (or some similar)
61encoding is used: hexadecimal values in the range C<0x40> - C<0x5A>
47f22e19 62indicate an uppercase letter, and C<0x20> encodes a space. So we might
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63assume it is a piece of text, which some are able to read like a tabloid;
64but others will have to get hold of an ASCII table and relive that
65firstgrader feeling. Not caring too much about which way to read this,
66we note that C<unpack> with the template code C<H> converts the contents
67of a sequence of bytes into the customary hexadecimal notation. Since
68"a sequence of" is a pretty vague indication of quantity, C<H> has been
69defined to convert just a single hexadecimal digit unless it is followed
70by a repeat count. An asterisk for the repeat count means to use whatever
71remains.
72
73The inverse operation - packing byte contents from a string of hexadecimal
74digits - is just as easily written. For instance:
75
4e848ca9 76 my $s = pack( 'H2' x 10, 30..39 );
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77 print "$s\n";
78
79Since we feed a list of ten 2-digit hexadecimal strings to C<pack>, the
80pack template should contain ten pack codes. If this is run on a computer
81with ASCII character coding, it will print C<0123456789>.
82
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83=head1 Packing Text
84
85Let's suppose you've got to read in a data file like this:
86
87 Date |Description | Income|Expenditure
9567c12e 88 01/24/2001 Zed's Camel Emporium 1147.99
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89 01/28/2001 Flea spray 24.99
90 01/29/2001 Camel rides to tourists 235.00
91
92How do we do it? You might think first to use C<split>; however, since
93C<split> collapses blank fields, you'll never know whether a record was
94income or expenditure. Oops. Well, you could always use C<substr>:
95
96 while (<>) {
97 my $date = substr($_, 0, 11);
98 my $desc = substr($_, 12, 27);
99 my $income = substr($_, 40, 7);
100 my $expend = substr($_, 52, 7);
101 ...
102 }
103
104It's not really a barrel of laughs, is it? In fact, it's worse than it
105may seem; the eagle-eyed may notice that the first field should only be
10610 characters wide, and the error has propagated right through the other
107numbers - which we've had to count by hand. So it's error-prone as well
108as horribly unfriendly.
109
110Or maybe we could use regular expressions:
7207e29d 111
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112 while (<>) {
113 my($date, $desc, $income, $expend) =
114 m|(\d\d/\d\d/\d{4}) (.{27}) (.{7})(.*)|;
115 ...
116 }
117
118Urgh. Well, it's a bit better, but - well, would you want to maintain
119that?
120
121Hey, isn't Perl supposed to make this sort of thing easy? Well, it does,
122if you use the right tools. C<pack> and C<unpack> are designed to help
123you out when dealing with fixed-width data like the above. Let's have a
124look at a solution with C<unpack>:
125
126 while (<>) {
127 my($date, $desc, $income, $expend) = unpack("A10xA27xA7A*", $_);
128 ...
129 }
130
131That looks a bit nicer; but we've got to take apart that weird template.
132Where did I pull that out of?
133
134OK, let's have a look at some of our data again; in fact, we'll include
135the headers, and a handy ruler so we can keep track of where we are.
136
137 1 2 3 4 5
138 1234567890123456789012345678901234567890123456789012345678
139 Date |Description | Income|Expenditure
140 01/28/2001 Flea spray 24.99
141 01/29/2001 Camel rides to tourists 235.00
142
47b6252e 143From this, we can see that the date column stretches from column 1 to
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144column 10 - ten characters wide. The C<pack>-ese for "character" is
145C<A>, and ten of them are C<A10>. So if we just wanted to extract the
146dates, we could say this:
147
148 my($date) = unpack("A10", $_);
149
150OK, what's next? Between the date and the description is a blank column;
151we want to skip over that. The C<x> template means "skip forward", so we
152want one of those. Next, we have another batch of characters, from 12 to
15338. That's 27 more characters, hence C<A27>. (Don't make the fencepost
154error - there are 27 characters between 12 and 38, not 26. Count 'em!)
155
156Now we skip another character and pick up the next 7 characters:
157
158 my($date,$description,$income) = unpack("A10xA27xA7", $_);
159
160Now comes the clever bit. Lines in our ledger which are just income and
161not expenditure might end at column 46. Hence, we don't want to tell our
162C<unpack> pattern that we B<need> to find another 12 characters; we'll
163just say "if there's anything left, take it". As you might guess from
164regular expressions, that's what the C<*> means: "use everything
165remaining".
166
167=over 3
168
169=item *
170
171Be warned, though, that unlike regular expressions, if the C<unpack>
172template doesn't match the incoming data, Perl will scream and die.
173
174=back
175
176
177Hence, putting it all together:
178
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179 my ($date, $description, $income, $expend) =
180 unpack("A10xA27xA7xA*", $_);
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181
182Now, that's our data parsed. I suppose what we might want to do now is
183total up our income and expenditure, and add another line to the end of
184our ledger - in the same format - saying how much we've brought in and
185how much we've spent:
186
187 while (<>) {
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188 my ($date, $desc, $income, $expend) =
189 unpack("A10xA27xA7xA*", $_);
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190 $tot_income += $income;
191 $tot_expend += $expend;
192 }
193
194 $tot_income = sprintf("%.2f", $tot_income); # Get them into
195 $tot_expend = sprintf("%.2f", $tot_expend); # "financial" format
196
197 $date = POSIX::strftime("%m/%d/%Y", localtime);
198
199 # OK, let's go:
200
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201 print pack("A10xA27xA7xA*", $date, "Totals",
202 $tot_income, $tot_expend);
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203
204Oh, hmm. That didn't quite work. Let's see what happened:
205
9567c12e 206 01/24/2001 Zed's Camel Emporium 1147.99
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207 01/28/2001 Flea spray 24.99
208 01/29/2001 Camel rides to tourists 1235.00
209 03/23/2001Totals 1235.001172.98
210
211OK, it's a start, but what happened to the spaces? We put C<x>, didn't
212we? Shouldn't it skip forward? Let's look at what L<perlfunc/pack> says:
213
214 x A null byte.
215
216Urgh. No wonder. There's a big difference between "a null byte",
217character zero, and "a space", character 32. Perl's put something
218between the date and the description - but unfortunately, we can't see
219it!
220
221What we actually need to do is expand the width of the fields. The C<A>
222format pads any non-existent characters with spaces, so we can use the
223additional spaces to line up our fields, like this:
224
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225 print pack("A11 A28 A8 A*", $date, "Totals",
226 $tot_income, $tot_expend);
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227
228(Note that you can put spaces in the template to make it more readable,
229but they don't translate to spaces in the output.) Here's what we got
230this time:
231
9567c12e 232 01/24/2001 Zed's Camel Emporium 1147.99
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233 01/28/2001 Flea spray 24.99
234 01/29/2001 Camel rides to tourists 1235.00
235 03/23/2001 Totals 1235.00 1172.98
236
237That's a bit better, but we still have that last column which needs to
238be moved further over. There's an easy way to fix this up:
239unfortunately, we can't get C<pack> to right-justify our fields, but we
240can get C<sprintf> to do it:
241
242 $tot_income = sprintf("%.2f", $tot_income);
243 $tot_expend = sprintf("%12.2f", $tot_expend);
244 $date = POSIX::strftime("%m/%d/%Y", localtime);
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245 print pack("A11 A28 A8 A*", $date, "Totals",
246 $tot_income, $tot_expend);
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247
248This time we get the right answer:
249
250 01/28/2001 Flea spray 24.99
251 01/29/2001 Camel rides to tourists 1235.00
252 03/23/2001 Totals 1235.00 1172.98
253
254So that's how we consume and produce fixed-width data. Let's recap what
255we've seen of C<pack> and C<unpack> so far:
256
257=over 3
258
259=item *
260
261Use C<pack> to go from several pieces of data to one fixed-width
262version; use C<unpack> to turn a fixed-width-format string into several
263pieces of data.
264
265=item *
266
267The pack format C<A> means "any character"; if you're C<pack>ing and
268you've run out of things to pack, C<pack> will fill the rest up with
269spaces.
270
271=item *
272
273C<x> means "skip a byte" when C<unpack>ing; when C<pack>ing, it means
274"introduce a null byte" - that's probably not what you mean if you're
275dealing with plain text.
276
277=item *
278
279You can follow the formats with numbers to say how many characters
280should be affected by that format: C<A12> means "take 12 characters";
281C<x6> means "skip 6 bytes" or "character 0, 6 times".
282
283=item *
284
285Instead of a number, you can use C<*> to mean "consume everything else
286left".
287
288B<Warning>: when packing multiple pieces of data, C<*> only means
289"consume all of the current piece of data". That's to say
290
291 pack("A*A*", $one, $two)
292
293packs all of C<$one> into the first C<A*> and then all of C<$two> into
294the second. This is a general principle: each format character
295corresponds to one piece of data to be C<pack>ed.
296
297=back
298
299
300
301=head1 Packing Numbers
302
303So much for textual data. Let's get onto the meaty stuff that C<pack>
304and C<unpack> are best at: handling binary formats for numbers. There is,
305of course, not just one binary format - life would be too simple - but
306Perl will do all the finicky labor for you.
307
308
309=head2 Integers
310
311Packing and unpacking numbers implies conversion to and from some
312I<specific> binary representation. Leaving floating point numbers
313aside for the moment, the salient properties of any such representation
314are:
315
316=over 4
317
318=item *
319
320the number of bytes used for storing the integer,
321
322=item *
323
324whether the contents are interpreted as a signed or unsigned number,
325
326=item *
327
328the byte ordering: whether the first byte is the least or most
329significant byte (or: little-endian or big-endian, respectively).
330
331=back
332
333So, for instance, to pack 20302 to a signed 16 bit integer in your
334computer's representation you write
335
336 my $ps = pack( 's', 20302 );
337
338Again, the result is a string, now containing 2 bytes. If you print
339this string (which is, generally, not recommended) you might see
340C<ON> or C<NO> (depending on your system's byte ordering) - or something
341entirely different if your computer doesn't use ASCII character encoding.
342Unpacking C<$ps> with the same template returns the original integer value:
343
344 my( $s ) = unpack( 's', $ps );
345
346This is true for all numeric template codes. But don't expect miracles:
47b6252e 347if the packed value exceeds the allotted byte capacity, high order bits
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348are silently discarded, and unpack certainly won't be able to pull them
349back out of some magic hat. And, when you pack using a signed template
350code such as C<s>, an excess value may result in the sign bit
351getting set, and unpacking this will smartly return a negative value.
352
35316 bits won't get you too far with integers, but there is C<l> and C<L>
354for signed and unsigned 32-bit integers. And if this is not enough and
355your system supports 64 bit integers you can push the limits much closer
356to infinity with pack codes C<q> and C<Q>. A notable exception is provided
357by pack codes C<i> and C<I> for signed and unsigned integers of the
358"local custom" variety: Such an integer will take up as many bytes as
359a local C compiler returns for C<sizeof(int)>, but it'll use I<at least>
36032 bits.
361
362Each of the integer pack codes C<sSlLqQ> results in a fixed number of bytes,
363no matter where you execute your program. This may be useful for some
364applications, but it does not provide for a portable way to pass data
365structures between Perl and C programs (bound to happen when you call
366XS extensions or the Perl function C<syscall>), or when you read or
367write binary files. What you'll need in this case are template codes that
368depend on what your local C compiler compiles when you code C<short> or
369C<unsigned long>, for instance. These codes and their corresponding
370byte lengths are shown in the table below. Since the C standard leaves
371much leeway with respect to the relative sizes of these data types, actual
372values may vary, and that's why the values are given as expressions in
373C and Perl. (If you'd like to use values from C<%Config> in your program
374you have to import it with C<use Config>.)
375
376 signed unsigned byte length in C byte length in Perl
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377 s! S! sizeof(short) $Config{shortsize}
378 i! I! sizeof(int) $Config{intsize}
379 l! L! sizeof(long) $Config{longsize}
d832b8f6 380 q! Q! sizeof(long long) $Config{longlongsize}
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381
382The C<i!> and C<I!> codes aren't different from C<i> and C<I>; they are
383tolerated for completeness' sake.
384
385
386=head2 Unpacking a Stack Frame
387
388Requesting a particular byte ordering may be necessary when you work with
47f22e19 389binary data coming from some specific architecture whereas your program could
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390run on a totally different system. As an example, assume you have 24 bytes
391containing a stack frame as it happens on an Intel 8086:
392
393 +---------+ +----+----+ +---------+
394 TOS: | IP | TOS+4:| FL | FH | FLAGS TOS+14:| SI |
395 +---------+ +----+----+ +---------+
396 | CS | | AL | AH | AX | DI |
397 +---------+ +----+----+ +---------+
398 | BL | BH | BX | BP |
399 +----+----+ +---------+
400 | CL | CH | CX | DS |
401 +----+----+ +---------+
402 | DL | DH | DX | ES |
403 +----+----+ +---------+
404
405First, we note that this time-honored 16-bit CPU uses little-endian order,
406and that's why the low order byte is stored at the lower address. To
9dc383df 407unpack such a (unsigned) short we'll have to use code C<v>. A repeat
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408count unpacks all 12 shorts:
409
410 my( $ip, $cs, $flags, $ax, $bx, $cd, $dx, $si, $di, $bp, $ds, $es ) =
411 unpack( 'v12', $frame );
412
413Alternatively, we could have used C<C> to unpack the individually
414accessible byte registers FL, FH, AL, AH, etc.:
415
416 my( $fl, $fh, $al, $ah, $bl, $bh, $cl, $ch, $dl, $dh ) =
417 unpack( 'C10', substr( $frame, 4, 10 ) );
418
419It would be nice if we could do this in one fell swoop: unpack a short,
420back up a little, and then unpack 2 bytes. Since Perl I<is> nice, it
421proffers the template code C<X> to back up one byte. Putting this all
422together, we may now write:
423
424 my( $ip, $cs,
425 $flags,$fl,$fh,
426 $ax,$al,$ah, $bx,$bl,$bh, $cx,$cl,$ch, $dx,$dl,$dh,
427 $si, $di, $bp, $ds, $es ) =
428 unpack( 'v2' . ('vXXCC' x 5) . 'v5', $frame );
429
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430(The clumsy construction of the template can be avoided - just read on!)
431
47f22e19 432We've taken some pains to construct the template so that it matches
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433the contents of our frame buffer. Otherwise we'd either get undefined values,
434or C<unpack> could not unpack all. If C<pack> runs out of items, it will
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435supply null strings (which are coerced into zeroes whenever the pack code
436says so).
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437
438
439=head2 How to Eat an Egg on a Net
440
441The pack code for big-endian (high order byte at the lowest address) is
442C<n> for 16 bit and C<N> for 32 bit integers. You use these codes
443if you know that your data comes from a compliant architecture, but,
444surprisingly enough, you should also use these pack codes if you
445exchange binary data, across the network, with some system that you
446know next to nothing about. The simple reason is that this
447order has been chosen as the I<network order>, and all standard-fearing
448programs ought to follow this convention. (This is, of course, a stern
449backing for one of the Lilliputian parties and may well influence the
450political development there.) So, if the protocol expects you to send
451a message by sending the length first, followed by just so many bytes,
452you could write:
453
454 my $buf = pack( 'N', length( $msg ) ) . $msg;
455
456or even:
457
458 my $buf = pack( 'NA*', length( $msg ), $msg );
459
460and pass C<$buf> to your send routine. Some protocols demand that the
461count should include the length of the count itself: then just add 4
5a0de581 462to the data length. (But make sure to read L</"Lengths and Widths"> before
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463you really code this!)
464
465
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466=head2 Byte-order modifiers
467
468In the previous sections we've learned how to use C<n>, C<N>, C<v> and
469C<V> to pack and unpack integers with big- or little-endian byte-order.
470While this is nice, it's still rather limited because it leaves out all
471kinds of signed integers as well as 64-bit integers. For example, if you
472wanted to unpack a sequence of signed big-endian 16-bit integers in a
473platform-independent way, you would have to write:
474
475 my @data = unpack 's*', pack 'S*', unpack 'n*', $buf;
476
c4ecfaf1 477This is ugly. As of Perl 5.9.2, there's a much nicer way to express your
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478desire for a certain byte-order: the C<E<gt>> and C<E<lt>> modifiers.
479C<E<gt>> is the big-endian modifier, while C<E<lt>> is the little-endian
480modifier. Using them, we could rewrite the above code as:
481
482 my @data = unpack 's>*', $buf;
483
484As you can see, the "big end" of the arrow touches the C<s>, which is a
485nice way to remember that C<E<gt>> is the big-endian modifier. The same
486obviously works for C<E<lt>>, where the "little end" touches the code.
487
488You will probably find these modifiers even more useful if you have
489to deal with big- or little-endian C structures. Be sure to read
5a0de581 490L</"Packing and Unpacking C Structures"> for more on that.
59f20ca5 491
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492
493=head2 Floating point Numbers
494
495For packing floating point numbers you have the choice between the
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496pack codes C<f>, C<d>, C<F> and C<D>. C<f> and C<d> pack into (or unpack
497from) single-precision or double-precision representation as it is provided
498by your system. If your systems supports it, C<D> can be used to pack and
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499unpack (C<long double>) values, which can offer even more resolution
500than C<f> or C<d>. B<Note that there are different long double formats.>
501
502C<F> packs an C<NV>, which is the floating point type used by Perl
503internally.
504
505There is no such thing as a network representation for reals, so if
506you want to send your real numbers across computer boundaries, you'd
507better stick to text representation, possibly using the hexadecimal
508float format (avoiding the decimal conversion loss), unless you're
509absolutely sure what's on the other end of the line. For the even more
510adventuresome, you can use the byte-order modifiers from the previous
511section also on floating point codes.
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512
513
514
515=head1 Exotic Templates
516
517
518=head2 Bit Strings
519
520Bits are the atoms in the memory world. Access to individual bits may
521have to be used either as a last resort or because it is the most
522convenient way to handle your data. Bit string (un)packing converts
523between strings containing a series of C<0> and C<1> characters and
524a sequence of bytes each containing a group of 8 bits. This is almost
525as simple as it sounds, except that there are two ways the contents of
526a byte may be written as a bit string. Let's have a look at an annotated
527byte:
528
529 7 6 5 4 3 2 1 0
530 +-----------------+
531 | 1 0 0 0 1 1 0 0 |
532 +-----------------+
533 MSB LSB
534
535It's egg-eating all over again: Some think that as a bit string this should
536be written "10001100" i.e. beginning with the most significant bit, others
537insist on "00110001". Well, Perl isn't biased, so that's why we have two bit
538string codes:
539
540 $byte = pack( 'B8', '10001100' ); # start with MSB
541 $byte = pack( 'b8', '00110001' ); # start with LSB
542
543It is not possible to pack or unpack bit fields - just integral bytes.
544C<pack> always starts at the next byte boundary and "rounds up" to the
545next multiple of 8 by adding zero bits as required. (If you do want bit
546fields, there is L<perlfunc/vec>. Or you could implement bit field
547handling at the character string level, using split, substr, and
548concatenation on unpacked bit strings.)
549
550To illustrate unpacking for bit strings, we'll decompose a simple
551status register (a "-" stands for a "reserved" bit):
552
553 +-----------------+-----------------+
554 | S Z - A - P - C | - - - - O D I T |
555 +-----------------+-----------------+
556 MSB LSB MSB LSB
557
558Converting these two bytes to a string can be done with the unpack
559template C<'b16'>. To obtain the individual bit values from the bit
47f22e19 560string we use C<split> with the "empty" separator pattern which dissects
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561into individual characters. Bit values from the "reserved" positions are
562simply assigned to C<undef>, a convenient notation for "I don't care where
563this goes".
564
49704364 565 ($carry, undef, $parity, undef, $auxcarry, undef, $zero, $sign,
34babc16 566 $trace, $interrupt, $direction, $overflow) =
47f22e19 567 split( //, unpack( 'b16', $status ) );
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568
569We could have used an unpack template C<'b12'> just as well, since the
570last 4 bits can be ignored anyway.
571
572
573=head2 Uuencoding
574
99f65d01 575Another odd-man-out in the template alphabet is C<u>, which packs a
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576"uuencoded string". ("uu" is short for Unix-to-Unix.) Chances are that
577you won't ever need this encoding technique which was invented to overcome
578the shortcomings of old-fashioned transmission mediums that do not support
579other than simple ASCII data. The essential recipe is simple: Take three
580bytes, or 24 bits. Split them into 4 six-packs, adding a space (0x20) to
581each. Repeat until all of the data is blended. Fold groups of 4 bytes into
582lines no longer than 60 and garnish them in front with the original byte count
583(incremented by 0x20) and a C<"\n"> at the end. - The C<pack> chef will
584prepare this for you, a la minute, when you select pack code C<u> on the menu:
585
586 my $uubuf = pack( 'u', $bindat );
587
588A repeat count after C<u> sets the number of bytes to put into an
589uuencoded line, which is the maximum of 45 by default, but could be
590set to some (smaller) integer multiple of three. C<unpack> simply ignores
591the repeat count.
592
593
594=head2 Doing Sums
595
596An even stranger template code is C<%>E<lt>I<number>E<gt>. First, because
597it's used as a prefix to some other template code. Second, because it
598cannot be used in C<pack> at all, and third, in C<unpack>, doesn't return the
599data as defined by the template code it precedes. Instead it'll give you an
600integer of I<number> bits that is computed from the data value by
601doing sums. For numeric unpack codes, no big feat is achieved:
602
603 my $buf = pack( 'iii', 100, 20, 3 );
604 print unpack( '%32i3', $buf ), "\n"; # prints 123
605
606For string values, C<%> returns the sum of the byte values saving
607you the trouble of a sum loop with C<substr> and C<ord>:
608
609 print unpack( '%32A*', "\x01\x10" ), "\n"; # prints 17
610
611Although the C<%> code is documented as returning a "checksum":
612don't put your trust in such values! Even when applied to a small number
613of bytes, they won't guarantee a noticeable Hamming distance.
614
615In connection with C<b> or C<B>, C<%> simply adds bits, and this can be put
616to good use to count set bits efficiently:
617
618 my $bitcount = unpack( '%32b*', $mask );
619
620And an even parity bit can be determined like this:
621
622 my $evenparity = unpack( '%1b*', $mask );
623
624
625=head2 Unicode
626
627Unicode is a character set that can represent most characters in most of
628the world's languages, providing room for over one million different
629characters. Unicode 3.1 specifies 94,140 characters: The Basic Latin
630characters are assigned to the numbers 0 - 127. The Latin-1 Supplement with
631characters that are used in several European languages is in the next
632range, up to 255. After some more Latin extensions we find the character
47b6252e 633sets from languages using non-Roman alphabets, interspersed with a
34babc16 634variety of symbol sets such as currency symbols, Zapf Dingbats or Braille.
f979aebc 635(You might want to visit L<http://www.unicode.org/> for a look at some of
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636them - my personal favourites are Telugu and Kannada.)
637
638The Unicode character sets associates characters with integers. Encoding
639these numbers in an equal number of bytes would more than double the
47b6252e 640requirements for storing texts written in Latin alphabets.
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641The UTF-8 encoding avoids this by storing the most common (from a western
642point of view) characters in a single byte while encoding the rarer
643ones in three or more bytes.
644
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645Perl uses UTF-8, internally, for most Unicode strings.
646
647So what has this got to do with C<pack>? Well, if you want to compose a
648Unicode string (that is internally encoded as UTF-8), you can do so by
649using template code C<U>. As an example, let's produce the Euro currency
650symbol (code number 0x20AC):
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651
652 $UTF8{Euro} = pack( 'U', 0x20AC );
2575c402 653 # Equivalent to: $UTF8{Euro} = "\x{20ac}";
34babc16 654
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655Inspecting C<$UTF8{Euro}> shows that it contains 3 bytes:
656"\xe2\x82\xac". However, it contains only 1 character, number 0x20AC.
657The round trip can be completed with C<unpack>:
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658
659 $Unicode{Euro} = unpack( 'U', $UTF8{Euro} );
660
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661Unpacking using the C<U> template code also works on UTF-8 encoded byte
662strings.
663
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664Usually you'll want to pack or unpack UTF-8 strings:
665
666 # pack and unpack the Hebrew alphabet
667 my $alefbet = pack( 'U*', 0x05d0..0x05ea );
668 my @hebrew = unpack( 'U*', $utf );
669
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670Please note: in the general case, you're better off using
671Encode::decode_utf8 to decode a UTF-8 encoded byte string to a Perl
38a44b82 672Unicode string, and Encode::encode_utf8 to encode a Perl Unicode string
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673to UTF-8 bytes. These functions provide means of handling invalid byte
674sequences and generally have a friendlier interface.
34babc16 675
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676=head2 Another Portable Binary Encoding
677
678The pack code C<w> has been added to support a portable binary data
679encoding scheme that goes way beyond simple integers. (Details can
f979aebc 680be found at L<http://Casbah.org/>, the Scarab project.) A BER (Binary Encoded
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681Representation) compressed unsigned integer stores base 128
682digits, most significant digit first, with as few digits as possible.
683Bit eight (the high bit) is set on each byte except the last. There
684is no size limit to BER encoding, but Perl won't go to extremes.
685
686 my $berbuf = pack( 'w*', 1, 128, 128+1, 128*128+127 );
687
688A hex dump of C<$berbuf>, with spaces inserted at the right places,
689shows 01 8100 8101 81807F. Since the last byte is always less than
690128, C<unpack> knows where to stop.
691
34babc16 692
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693=head1 Template Grouping
694
695Prior to Perl 5.8, repetitions of templates had to be made by
696C<x>-multiplication of template strings. Now there is a better way as
697we may use the pack codes C<(> and C<)> combined with a repeat count.
698The C<unpack> template from the Stack Frame example can simply
699be written like this:
700
701 unpack( 'v2 (vXXCC)5 v5', $frame )
702
703Let's explore this feature a little more. We'll begin with the equivalent of
704
705 join( '', map( substr( $_, 0, 1 ), @str ) )
706
707which returns a string consisting of the first character from each string.
708Using pack, we can write
709
710 pack( '(A)'.@str, @str )
711
712or, because a repeat count C<*> means "repeat as often as required",
713simply
714
715 pack( '(A)*', @str )
716
717(Note that the template C<A*> would only have packed C<$str[0]> in full
718length.)
ffc145e8 719
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720To pack dates stored as triplets ( day, month, year ) in an array C<@dates>
721into a sequence of byte, byte, short integer we can write
722
723 $pd = pack( '(CCS)*', map( @$_, @dates ) );
724
725To swap pairs of characters in a string (with even length) one could use
726several techniques. First, let's use C<x> and C<X> to skip forward and back:
727
728 $s = pack( '(A)*', unpack( '(xAXXAx)*', $s ) );
729
730We can also use C<@> to jump to an offset, with 0 being the position where
731we were when the last C<(> was encountered:
732
733 $s = pack( '(A)*', unpack( '(@1A @0A @2)*', $s ) );
734
735Finally, there is also an entirely different approach by unpacking big
736endian shorts and packing them in the reverse byte order:
737
738 $s = pack( '(v)*', unpack( '(n)*', $s );
739
740
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741=head1 Lengths and Widths
742
743=head2 String Lengths
744
745In the previous section we've seen a network message that was constructed
746by prefixing the binary message length to the actual message. You'll find
747that packing a length followed by so many bytes of data is a
748frequently used recipe since appending a null byte won't work
47b6252e 749if a null byte may be part of the data. Here is an example where both
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750techniques are used: after two null terminated strings with source and
751destination address, a Short Message (to a mobile phone) is sent after
752a length byte:
753
754 my $msg = pack( 'Z*Z*CA*', $src, $dst, length( $sm ), $sm );
755
756Unpacking this message can be done with the same template:
757
758 ( $src, $dst, $len, $sm ) = unpack( 'Z*Z*CA*', $msg );
759
47b6252e 760There's a subtle trap lurking in the offing: Adding another field after
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761the Short Message (in variable C<$sm>) is all right when packing, but this
762cannot be unpacked naively:
763
764 # pack a message
765 my $msg = pack( 'Z*Z*CA*C', $src, $dst, length( $sm ), $sm, $prio );
7207e29d 766
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767 # unpack fails - $prio remains undefined!
768 ( $src, $dst, $len, $sm, $prio ) = unpack( 'Z*Z*CA*C', $msg );
769
770The pack code C<A*> gobbles up all remaining bytes, and C<$prio> remains
771undefined! Before we let disappointment dampen the morale: Perl's got
772the trump card to make this trick too, just a little further up the sleeve.
773Watch this:
774
775 # pack a message: ASCIIZ, ASCIIZ, length/string, byte
776 my $msg = pack( 'Z* Z* C/A* C', $src, $dst, $sm, $prio );
777
778 # unpack
779 ( $src, $dst, $sm, $prio ) = unpack( 'Z* Z* C/A* C', $msg );
780
781Combining two pack codes with a slash (C</>) associates them with a single
782value from the argument list. In C<pack>, the length of the argument is
783taken and packed according to the first code while the argument itself
784is added after being converted with the template code after the slash.
785This saves us the trouble of inserting the C<length> call, but it is
786in C<unpack> where we really score: The value of the length byte marks the
787end of the string to be taken from the buffer. Since this combination
f8b4d74f 788doesn't make sense except when the second pack code isn't C<a*>, C<A*>
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789or C<Z*>, Perl won't let you.
790
791The pack code preceding C</> may be anything that's fit to represent a
792number: All the numeric binary pack codes, and even text codes such as
793C<A4> or C<Z*>:
794
795 # pack/unpack a string preceded by its length in ASCII
796 my $buf = pack( 'A4/A*', "Humpty-Dumpty" );
797 # unpack $buf: '13 Humpty-Dumpty'
798 my $txt = unpack( 'A4/A*', $buf );
799
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800C</> is not implemented in Perls before 5.6, so if your code is required to
801work on older Perls you'll need to C<unpack( 'Z* Z* C')> to get the length,
802then use it to make a new unpack string. For example
803
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804 # pack a message: ASCIIZ, ASCIIZ, length, string, byte
805 # (5.005 compatible)
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806 my $msg = pack( 'Z* Z* C A* C', $src, $dst, length $sm, $sm, $prio );
807
808 # unpack
809 ( undef, undef, $len) = unpack( 'Z* Z* C', $msg );
810 ($src, $dst, $sm, $prio) = unpack ( "Z* Z* x A$len C", $msg );
811
812But that second C<unpack> is rushing ahead. It isn't using a simple literal
813string for the template. So maybe we should introduce...
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814
815=head2 Dynamic Templates
816
817So far, we've seen literals used as templates. If the list of pack
818items doesn't have fixed length, an expression constructing the
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819template is required (whenever, for some reason, C<()*> cannot be used).
820Here's an example: To store named string values in a way that can be
821conveniently parsed by a C program, we create a sequence of names and
822null terminated ASCII strings, with C<=> between the name and the value,
823followed by an additional delimiting null byte. Here's how:
34babc16 824
49704364 825 my $env = pack( '(A*A*Z*)' . keys( %Env ) . 'C',
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826 map( { ( $_, '=', $Env{$_} ) } keys( %Env ) ), 0 );
827
828Let's examine the cogs of this byte mill, one by one. There's the C<map>
829call, creating the items we intend to stuff into the C<$env> buffer:
830to each key (in C<$_>) it adds the C<=> separator and the hash entry value.
831Each triplet is packed with the template code sequence C<A*A*Z*> that
49704364 832is repeated according to the number of keys. (Yes, that's what the C<keys>
fe854a6f 833function returns in scalar context.) To get the very last null byte,
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834we add a C<0> at the end of the C<pack> list, to be packed with C<C>.
835(Attentive readers may have noticed that we could have omitted the 0.)
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836
837For the reverse operation, we'll have to determine the number of items
838in the buffer before we can let C<unpack> rip it apart:
839
47b6252e 840 my $n = $env =~ tr/\0// - 1;
49704364 841 my %env = map( split( /=/, $_ ), unpack( "(Z*)$n", $env ) );
34babc16 842
47b6252e 843The C<tr> counts the null bytes. The C<unpack> call returns a list of
47f22e19 844name-value pairs each of which is taken apart in the C<map> block.
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845
846
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847=head2 Counting Repetitions
848
849Rather than storing a sentinel at the end of a data item (or a list of items),
850we could precede the data with a count. Again, we pack keys and values of
851a hash, preceding each with an unsigned short length count, and up front
852we store the number of pairs:
853
854 my $env = pack( 'S(S/A* S/A*)*', scalar keys( %Env ), %Env );
855
856This simplifies the reverse operation as the number of repetitions can be
857unpacked with the C</> code:
858
859 my %env = unpack( 'S/(S/A* S/A*)', $env );
860
861Note that this is one of the rare cases where you cannot use the same
862template for C<pack> and C<unpack> because C<pack> can't determine
863a repeat count for a C<()>-group.
864
865
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866=head2 Intel HEX
867
868Intel HEX is a file format for representing binary data, mostly for
869programming various chips, as a text file. (See
870L<http://en.wikipedia.org/wiki/.hex> for a detailed description, and
871L<http://en.wikipedia.org/wiki/SREC_(file_format)> for the Motorola
872S-record format, which can be unravelled using the same technique.)
873Each line begins with a colon (':') and is followed by a sequence of
874hexadecimal characters, specifying a byte count I<n> (8 bit),
875an address (16 bit, big endian), a record type (8 bit), I<n> data bytes
876and a checksum (8 bit) computed as the least significant byte of the two's
877complement sum of the preceding bytes. Example: C<:0300300002337A1E>.
878
879The first step of processing such a line is the conversion, to binary,
880of the hexadecimal data, to obtain the four fields, while checking the
881checksum. No surprise here: we'll start with a simple C<pack> call to
882convert everything to binary:
883
884 my $binrec = pack( 'H*', substr( $hexrec, 1 ) );
885
886The resulting byte sequence is most convenient for checking the checksum.
887Don't slow your program down with a for loop adding the C<ord> values
888of this string's bytes - the C<unpack> code C<%> is the thing to use
889for computing the 8-bit sum of all bytes, which must be equal to zero:
890
891 die unless unpack( "%8C*", $binrec ) == 0;
892
893Finally, let's get those four fields. By now, you shouldn't have any
894problems with the first three fields - but how can we use the byte count
895of the data in the first field as a length for the data field? Here
896the codes C<x> and C<X> come to the rescue, as they permit jumping
897back and forth in the string to unpack.
898
899 my( $addr, $type, $data ) = unpack( "x n C X4 C x3 /a", $bin );
900
901Code C<x> skips a byte, since we don't need the count yet. Code C<n> takes
902care of the 16-bit big-endian integer address, and C<C> unpacks the
903record type. Being at offset 4, where the data begins, we need the count.
904C<X4> brings us back to square one, which is the byte at offset 0.
905Now we pick up the count, and zoom forth to offset 4, where we are
906now fully furnished to extract the exact number of data bytes, leaving
907the trailing checksum byte alone.
908
909
910
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911=head1 Packing and Unpacking C Structures
912
913In previous sections we have seen how to pack numbers and character
914strings. If it were not for a couple of snags we could conclude this
915section right away with the terse remark that C structures don't
916contain anything else, and therefore you already know all there is to it.
917Sorry, no: read on, please.
918
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919If you have to deal with a lot of C structures, and don't want to
920hack all your template strings manually, you'll probably want to have
921a look at the CPAN module C<Convert::Binary::C>. Not only can it parse
922your C source directly, but it also has built-in support for all the
923odds and ends described further on in this section.
924
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925=head2 The Alignment Pit
926
927In the consideration of speed against memory requirements the balance
928has been tilted in favor of faster execution. This has influenced the
929way C compilers allocate memory for structures: On architectures
930where a 16-bit or 32-bit operand can be moved faster between places in
931memory, or to or from a CPU register, if it is aligned at an even or
932multiple-of-four or even at a multiple-of eight address, a C compiler
933will give you this speed benefit by stuffing extra bytes into structures.
934If you don't cross the C shoreline this is not likely to cause you any
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935grief (although you should care when you design large data structures,
936or you want your code to be portable between architectures (you do want
937that, don't you?)).
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938
939To see how this affects C<pack> and C<unpack>, we'll compare these two
940C structures:
941
942 typedef struct {
943 char c1;
944 short s;
945 char c2;
946 long l;
947 } gappy_t;
948
949 typedef struct {
950 long l;
951 short s;
952 char c1;
953 char c2;
954 } dense_t;
955
956Typically, a C compiler allocates 12 bytes to a C<gappy_t> variable, but
957requires only 8 bytes for a C<dense_t>. After investigating this further,
958we can draw memory maps, showing where the extra 4 bytes are hidden:
959
960 0 +4 +8 +12
961 +--+--+--+--+--+--+--+--+--+--+--+--+
962 |c1|xx| s |c2|xx|xx|xx| l | xx = fill byte
963 +--+--+--+--+--+--+--+--+--+--+--+--+
964 gappy_t
965
966 0 +4 +8
967 +--+--+--+--+--+--+--+--+
968 | l | h |c1|c2|
969 +--+--+--+--+--+--+--+--+
970 dense_t
971
972And that's where the first quirk strikes: C<pack> and C<unpack>
973templates have to be stuffed with C<x> codes to get those extra fill bytes.
974
975The natural question: "Why can't Perl compensate for the gaps?" warrants
976an answer. One good reason is that C compilers might provide (non-ANSI)
977extensions permitting all sorts of fancy control over the way structures
978are aligned, even at the level of an individual structure field. And, if
979this were not enough, there is an insidious thing called C<union> where
980the amount of fill bytes cannot be derived from the alignment of the next
981item alone.
982
983OK, so let's bite the bullet. Here's one way to get the alignment right
984by inserting template codes C<x>, which don't take a corresponding item
985from the list:
986
987 my $gappy = pack( 'cxs cxxx l!', $c1, $s, $c2, $l );
988
989Note the C<!> after C<l>: We want to make sure that we pack a long
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990integer as it is compiled by our C compiler. And even now, it will only
991work for the platforms where the compiler aligns things as above.
992And somebody somewhere has a platform where it doesn't.
993[Probably a Cray, where C<short>s, C<int>s and C<long>s are all 8 bytes. :-)]
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994
995Counting bytes and watching alignments in lengthy structures is bound to
996be a drag. Isn't there a way we can create the template with a simple
997program? Here's a C program that does the trick:
998
999 #include <stdio.h>
1000 #include <stddef.h>
1001
1002 typedef struct {
1003 char fc1;
1004 short fs;
1005 char fc2;
1006 long fl;
1007 } gappy_t;
1008
1009 #define Pt(struct,field,tchar) \
1010 printf( "@%d%s ", offsetof(struct,field), # tchar );
1011
d832b8f6 1012 int main() {
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1013 Pt( gappy_t, fc1, c );
1014 Pt( gappy_t, fs, s! );
1015 Pt( gappy_t, fc2, c );
1016 Pt( gappy_t, fl, l! );
1017 printf( "\n" );
1018 }
1019
1020The output line can be used as a template in a C<pack> or C<unpack> call:
1021
1022 my $gappy = pack( '@0c @2s! @4c @8l!', $c1, $s, $c2, $l );
1023
1024Gee, yet another template code - as if we hadn't plenty. But
1025C<@> saves our day by enabling us to specify the offset from the beginning
1026of the pack buffer to the next item: This is just the value
1027the C<offsetof> macro (defined in C<E<lt>stddef.hE<gt>>) returns when
1028given a C<struct> type and one of its field names ("member-designator" in
1029C standardese).
1030
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1031Neither using offsets nor adding C<x>'s to bridge the gaps is satisfactory.
1032(Just imagine what happens if the structure changes.) What we really need
1033is a way of saying "skip as many bytes as required to the next multiple of N".
1034In fluent Templatese, you say this with C<x!N> where N is replaced by the
1035appropriate value. Here's the next version of our struct packaging:
1036
1037 my $gappy = pack( 'c x!2 s c x!4 l!', $c1, $s, $c2, $l );
1038
1039That's certainly better, but we still have to know how long all the
1040integers are, and portability is far away. Rather than C<2>,
1041for instance, we want to say "however long a short is". But this can be
1042done by enclosing the appropriate pack code in brackets: C<[s]>. So, here's
1043the very best we can do:
1044
1045 my $gappy = pack( 'c x![s] s c x![l!] l!', $c1, $s, $c2, $l );
1046
34babc16 1047
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1048=head2 Dealing with Endian-ness
1049
1050Now, imagine that we want to pack the data for a machine with a
1051different byte-order. First, we'll have to figure out how big the data
1052types on the target machine really are. Let's assume that the longs are
105332 bits wide and the shorts are 16 bits wide. You can then rewrite the
1054template as:
1055
1056 my $gappy = pack( 'c x![s] s c x![l] l', $c1, $s, $c2, $l );
1057
1058If the target machine is little-endian, we could write:
1059
1060 my $gappy = pack( 'c x![s] s< c x![l] l<', $c1, $s, $c2, $l );
1061
1062This forces the short and the long members to be little-endian, and is
1063just fine if you don't have too many struct members. But we could also
1064use the byte-order modifier on a group and write the following:
1065
1066 my $gappy = pack( '( c x![s] s c x![l] l )<', $c1, $s, $c2, $l );
1067
1068This is not as short as before, but it makes it more obvious that we
1069intend to have little-endian byte-order for a whole group, not only
1070for individual template codes. It can also be more readable and easier
1071to maintain.
1072
1073
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1074=head2 Alignment, Take 2
1075
1076I'm afraid that we're not quite through with the alignment catch yet. The
1077hydra raises another ugly head when you pack arrays of structures:
1078
1079 typedef struct {
1080 short count;
1081 char glyph;
1082 } cell_t;
1083
1084 typedef cell_t buffer_t[BUFLEN];
1085
1086Where's the catch? Padding is neither required before the first field C<count>,
1087nor between this and the next field C<glyph>, so why can't we simply pack
1088like this:
1089
1090 # something goes wrong here:
1091 pack( 's!a' x @buffer,
1092 map{ ( $_->{count}, $_->{glyph} ) } @buffer );
1093
1094This packs C<3*@buffer> bytes, but it turns out that the size of
1095C<buffer_t> is four times C<BUFLEN>! The moral of the story is that
1096the required alignment of a structure or array is propagated to the
1097next higher level where we have to consider padding I<at the end>
1098of each component as well. Thus the correct template is:
1099
1100 pack( 's!ax' x @buffer,
1101 map{ ( $_->{count}, $_->{glyph} ) } @buffer );
1102
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1103=head2 Alignment, Take 3
1104
1105And even if you take all the above into account, ANSI still lets this:
1106
1107 typedef struct {
1108 char foo[2];
1109 } foo_t;
34babc16 1110
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1111vary in size. The alignment constraint of the structure can be greater than
1112any of its elements. [And if you think that this doesn't affect anything
1113common, dismember the next cellphone that you see. Many have ARM cores, and
1114the ARM structure rules make C<sizeof (foo_t)> == 4]
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JH
1115
1116=head2 Pointers for How to Use Them
1117
1118The title of this section indicates the second problem you may run into
1119sooner or later when you pack C structures. If the function you intend
1120to call expects a, say, C<void *> value, you I<cannot> simply take
1121a reference to a Perl variable. (Although that value certainly is a
1122memory address, it's not the address where the variable's contents are
1123stored.)
1124
1125Template code C<P> promises to pack a "pointer to a fixed length string".
1126Isn't this what we want? Let's try:
1127
1128 # allocate some storage and pack a pointer to it
1129 my $memory = "\x00" x $size;
1130 my $memptr = pack( 'P', $memory );
1131
1132But wait: doesn't C<pack> just return a sequence of bytes? How can we pass this
1133string of bytes to some C code expecting a pointer which is, after all,
1134nothing but a number? The answer is simple: We have to obtain the numeric
1135address from the bytes returned by C<pack>.
1136
1137 my $ptr = unpack( 'L!', $memptr );
1138
1139Obviously this assumes that it is possible to typecast a pointer
1140to an unsigned long and vice versa, which frequently works but should not
1141be taken as a universal law. - Now that we have this pointer the next question
1142is: How can we put it to good use? We need a call to some C function
1143where a pointer is expected. The read(2) system call comes to mind:
1144
1145 ssize_t read(int fd, void *buf, size_t count);
1146
1147After reading L<perlfunc> explaining how to use C<syscall> we can write
1148this Perl function copying a file to standard output:
1149
b98b4a71 1150 require 'syscall.ph'; # run h2ph to generate this file
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1151 sub cat($){
1152 my $path = shift();
1153 my $size = -s $path;
1154 my $memory = "\x00" x $size; # allocate some memory
1155 my $ptr = unpack( 'L', pack( 'P', $memory ) );
1156 open( F, $path ) || die( "$path: cannot open ($!)\n" );
1157 my $fd = fileno(F);
1158 my $res = syscall( &SYS_read, fileno(F), $ptr, $size );
1159 print $memory;
1160 close( F );
1161 }
1162
1163This is neither a specimen of simplicity nor a paragon of portability but
1164it illustrates the point: We are able to sneak behind the scenes and
1165access Perl's otherwise well-guarded memory! (Important note: Perl's
1166C<syscall> does I<not> require you to construct pointers in this roundabout
1167way. You simply pass a string variable, and Perl forwards the address.)
1168
1169How does C<unpack> with C<P> work? Imagine some pointer in the buffer
1170about to be unpacked: If it isn't the null pointer (which will smartly
1171produce the C<undef> value) we have a start address - but then what?
1172Perl has no way of knowing how long this "fixed length string" is, so
1173it's up to you to specify the actual size as an explicit length after C<P>.
1174
1175 my $mem = "abcdefghijklmn";
1176 print unpack( 'P5', pack( 'P', $mem ) ); # prints "abcde"
1177
1178As a consequence, C<pack> ignores any number or C<*> after C<P>.
1179
1180
1181Now that we have seen C<P> at work, we might as well give C<p> a whirl.
1182Why do we need a second template code for packing pointers at all? The
1183answer lies behind the simple fact that an C<unpack> with C<p> promises
1184a null-terminated string starting at the address taken from the buffer,
1185and that implies a length for the data item to be returned:
1186
1187 my $buf = pack( 'p', "abc\x00efhijklmn" );
1188 print unpack( 'p', $buf ); # prints "abc"
1189
1190
1191
1192Albeit this is apt to be confusing: As a consequence of the length being
1193implied by the string's length, a number after pack code C<p> is a repeat
1194count, not a length as after C<P>.
1195
1196
1197Using C<pack(..., $x)> with C<P> or C<p> to get the address where C<$x> is
1198actually stored must be used with circumspection. Perl's internal machinery
1199considers the relation between a variable and that address as its very own
1200private matter and doesn't really care that we have obtained a copy. Therefore:
1201
1202=over 4
1203
1204=item *
1205
1206Do not use C<pack> with C<p> or C<P> to obtain the address of variable
1207that's bound to go out of scope (and thereby freeing its memory) before you
1208are done with using the memory at that address.
1209
1210=item *
1211
1212Be very careful with Perl operations that change the value of the
1213variable. Appending something to the variable, for instance, might require
1214reallocation of its storage, leaving you with a pointer into no-man's land.
1215
1216=item *
1217
1218Don't think that you can get the address of a Perl variable
1219when it is stored as an integer or double number! C<pack('P', $x)> will
1220force the variable's internal representation to string, just as if you
1221had written something like C<$x .= ''>.
1222
1223=back
1224
1225It's safe, however, to P- or p-pack a string literal, because Perl simply
1226allocates an anonymous variable.
1227
1228
1229
1230=head1 Pack Recipes
1231
1232Here are a collection of (possibly) useful canned recipes for C<pack>
1233and C<unpack>:
1234
1235 # Convert IP address for socket functions
1236 pack( "C4", split /\./, "123.4.5.6" );
1237
1238 # Count the bits in a chunk of memory (e.g. a select vector)
1239 unpack( '%32b*', $mask );
1240
1241 # Determine the endianness of your system
1242 $is_little_endian = unpack( 'c', pack( 's', 1 ) );
1243 $is_big_endian = unpack( 'xc', pack( 's', 1 ) );
1244
1245 # Determine the number of bits in a native integer
1246 $bits = unpack( '%32I!', ~0 );
1247
1248 # Prepare argument for the nanosleep system call
1249 my $timespec = pack( 'L!L!', $secs, $nanosecs );
1250
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1251For a simple memory dump we unpack some bytes into just as
1252many pairs of hex digits, and use C<map> to handle the traditional
1253spacing - 16 bytes to a line:
1254
34babc16 1255 my $i;
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1256 print map( ++$i % 16 ? "$_ " : "$_\n",
1257 unpack( 'H2' x length( $mem ), $mem ) ),
f8b4d74f 1258 length( $mem ) % 16 ? "\n" : '';
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1259
1260
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WL
1261=head1 Funnies Section
1262
1263 # Pulling digits out of nowhere...
1264 print unpack( 'C', pack( 'x' ) ),
1265 unpack( '%B*', pack( 'A' ) ),
1266 unpack( 'H', pack( 'A' ) ),
1267 unpack( 'A', unpack( 'C', pack( 'A' ) ) ), "\n";
1268
1269 # One for the road ;-)
1270 my $advice = pack( 'all u can in a van' );
1271
1272
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1273=head1 Authors
1274
1275Simon Cozens and Wolfgang Laun.
1276